Answer:
1.51×10²³ atoms.
Explanation:
From the question given above, the following data were obtained:
Mass of Calcium (Ca = 10 g
Number of atom of Calcium (Ca) =?
The number of atoms present in 10 g of Ca be obtained as follow:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This implies that 1 mole Ca contains 6.02×10²³ atoms.
1 mole of Ca = 40 g.
Now, if 40 g of Ca contains 6.02×10²³ atoms.
Therefore, 10 g of Ca will contain = (10 × 6.02×10²³) / 40 = 1.51×10²³ atoms.
Thus, 10 g of calcium contains 1.51×10²³ atoms.
Answer:
B (Final mass of the metal)
Explanation:
The independent variable in this experiment is the amount of acid the scientist pours on the metal, and the only variable in the list dependent on the amount of acid poured on the metal is the final mass of the metal. Therefore, the final mass of the metal is the dependent variable in the experiment.
Answer:
answer c the field strength is the same at points a and b
Answer
Explanation:
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C)
7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms