The answer is 7.33 g.
<span>To calculate this, we will use the the ideal gas law:
PV = nRT
where
P - pressure of the gas,
V - volume of the gas,
n - amount of substance of gas,
R - gas constant,
T - temperature of the gas.</span>
Since the amount of substance of gas (n) can be expressed as mass (m) divided by molar mass (M), then:
PV = RTm/M
It is given:
P = 0.98 atm
V = 10.2 l
T = 26°C = 299.15 K
R = 0.082 l atm/Kmol (gas constant)
M (H2O) = 2Ar(H) + Ar(O) = 2*1 + 16 = 2 + 16 = 18g
m = ?
Since PV = RTm/M, then:
m = PVM/RT
m = 0.98 · 10.2 · 18 / 0.082 · 299.15 = 179.928/24.5303 = 7.33 g
Answer: 27 is A and 28 is C.
Explanation: I’ll explain 28 but not 27 because that’s just definitions.
In CuSO4 there is a Cu, an S, and 4 O molecules. Add them up you get 6.
The molecular mass of carbon monoxide (CO) is 28 g/mol
<u><em>calculation</em></u>
The molecular mass of CO = atomic mass of C + atomic mass of O
From periodic table the atomic mass of C = 12 g/mol and for O = 16 g/mol
Therefore the molecular mass of Co = 12 g/mol + 16 g/mol = 28 g/mol
Answer:
2 ATP
Explanation:
glycolysis is the beginning of cellular respiration and it yielded net ATP of two produced from 1,3 bisphosphoglycerate conversion to 3-phosphoglycerate (2 ATP) and conversion of phosphoenolpyruvate to pyruvate ( 2ATP). One will recall that 2 ATP had been expended in the conversion of glucose to glucose-6-phosphate, and in the conversion of fructose-6-phosphate to fructose -1,6- bisphosphate. Other product of glycolysis are 2 NADH, 2 Pyruvate that may go into kreb cycle for further energy production depending on the organism type of respiration.
