Amount of moles of water is 4.36 mol
Explanation: M(C2H2) = 2·12.01 + 2·1.008 = 26.036 g/mol
Amount of substance is n= m/M= 56.8 g / 26.036 g/mol= 2.18159 mol
Water is needed 2·2.18 mol = 4.36 mol
Answer:
1.343 atm
Explanation:
We are given the following;
Pressure, p = ?
Volume v = 27 L
Mass of oxygen = 44.9 g
Temperature, T = 315 K
The formular relating all these variables is the equation;
PV = nRT
where R = gas constant = 0.08206 L atm / mole K
To obtain n, we use;
number of moles, n = Mass / molar mass = 44.9 / 32 = 1.403 moles
From the ideal gas equation;
P = nRT / V
P = 1.403 * 0.08206 * 315 / 27
P = 36.27 / 27 = 1.343 atm
