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faust18 [17]
3 years ago
11

Determine the molar mass for the element Zn

Chemistry
1 answer:
Molodets [167]3 years ago
5 0
The molar mass is 65.38 u
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Write a balanced chemical equation showing how each metal oxide reacts with HCl.
larisa86 [58]

Answer:

ZnO(s) + 2HCl(aq) ------> ZnCl2(aq) + H2O(l)

Na2O(s) + 2HCl(aq) -----> 2NaCl(aq) + H2O(l)

Rb2O(s) + 2HCl(aq) -----> 2RbCl(aq) + H2O(l)

NiO(s) + 2HCl(aq) --------> NiCl2(aq) + H2O(l)

MgO(s) + 2HI(aq) -----> MgI2(aq) + H2O(l)

Na2O(s) + 2HI(aq) -----> 2NaI(aq) + H2O(l)

CaO(s) + 2HI(aq) ----> CaI2(aq) + H2O(l)

Explanation:

Let us recall that the oxides of metals are basic in nature. These basic metal oxides can react with acids to form salt and water only.

In the reactions above, HCl and HI were reacted with different metal oxides and the corresponding salts of each metal and water was formed as shown.

3 0
3 years ago
Which of the following is the correct formula for sulfuric acid?
kondor19780726 [428]
D. H2SO4 would be correct!

6 0
3 years ago
Read 2 more answers
A rock is an example
sveticcg [70]

Answer:

the correct answer is option ( B ) rocks cannot change their volume ,shape, and size

because a solid substance cannot change its, volume, shape and size

Hope it helps you

have a nice day

3 0
2 years ago
PLEASE HELP!!!!LIKE NOW!!!
dsp73

I'm not completely sure on this and I apologize if it's wrong, but I believe it's  B) Newton's Law.

6 0
3 years ago
Calculate the volume of the gas when the pressure of the gas is 1.60 atm at a temperature of 298 K. There are 160. mol of gas in
LekaFEV [45]

Answer:

2445 L

Explanation:

Given:  

Pressure = 1.60 atm

Temperature = 298 K

Volume = ?

n =  160 mol

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 08206 L.atm/K.mol

Applying the equation as:

1.60 atm × V = 160 mol × 0.08206 L.atm/K.mol × 298 K  

<u>⇒V = 2445.39 L</u>

Answer to four significant digits, Volume = 2445 L

6 0
3 years ago
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