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Hoochie [10]
3 years ago
9

The width of Florida is 4/5 of its length if the length of Florida is about 450 miles what is the approximate width

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0
4/5 = 0.8

.8 * 450 = 360 miles
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GR9 MATH- REDUCE TO LOWEST TERMS:
Alika [10]

Answer:

the answer is f check and divide all the choices and you will get the answer I am sorry if I am wrong

8 0
3 years ago
Find the distance between the points (-2, 3) and (5, -1). Round to the nearest<br>tenth.​
Alexeev081 [22]

Answer:

8.062258

Step-by-step explanation:

d = 8.062258

For:

(-2, 3)

(5, -1)

Distance Equation Solution:

d=√(5−(−2))2+(−1−3)2

d=√(7)2+(−4)2

d=√49+16

d=6–√5

I belive the answer is

d=8.062258

7 0
3 years ago
If the radius of a circle is 5 units, in square units what is the sector area given m(arc)=142
Rufina [12.5K]

Answer:

The correct option is  30.6

Therefore,

Area of Sector is 30.6 units².

Step-by-step explanation:

Given:

Central angle = θ = 142°

Radius = r = 5 units

pi = 3.14

To Find:

Area of Sector = ?

Solution:

If the θ  measured in degree then the Area of Sector is given as

\textrm{Area of Sector}=\dfrac{\theta}{360\°}\times \pi r^{2}

Where r = radius, θ = Central angle

On substituting the values we get

\textrm{Area of Sector}=\dfrac{142}{360\°}\times \pi (5)^{2}

\textrm{Area of Sector}=0.39\times 3.14\times (5)^{2}

\textrm{Area of Sector}=30.615\ units^{2}

Therefore,

Area of Sector is 30.6 units².

3 0
3 years ago
If the diameter of a circle is 9 cm, then its circumference is 56.52 cm.<br><br> True or false?
Brrunno [24]
Circumference 
2*pi*r
2*(22/7)*(9/2)
2*(11/7)*9
198 / 7
28.28 cm

so 56.52 is not correct
3 0
3 years ago
The figure is made up of a cone and hemisphere. To the nearest whole number, what is the volume of this figure? Use 3.14 to appr
Finger [1]

Answer:

Volume=469cm³

Step-by-step explanation:

[tex]

Volume,V=Volume Cone + Volume\ of Hemisphere\\\\

Volume Cone,V1=\pi*r^2*\frac{h}{3}=\pi*4^2*\frac{12}{3}\\    \\

                     =201.06cm^3\\

Volume of Hemisphere,V2=2*\pi*\frac{r^3}{3}\\

                                            =2*\pi*\frac{4^3}{3}=268.083cm^3\\

Volume=V1+V2=201.06+268.08\\

            =469cm^3

[\tex]

3 0
3 years ago
Read 2 more answers
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