Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
1. 50 * 1,000 = 50,000
2. 49,001 + 999 = 50,000
3. 5 * 10,000 = 50,000
4. 100,000/2 = 50,000
5. 20,000 + 30,000 = 50,000
6. 50,000/1 = 50,000
7. 90,000 - 40,000 = 50,000
8. 10 + 49,990 = 50,000
9. 5,000 * 10 = 50,000
10. 1,000,000/20 = 50,000
Answer:
How is that possible
Step-by-step explanation:
Answer:
it means when x =0
so 6*0+12y=60
12y=60
y=5
Step-by-step explanation: