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timama [110]
4 years ago
10

The capital gains yield equals _________

Business
1 answer:
Arlecino [84]4 years ago
7 0

Answer:

Appreciation in Investment Value = Percentage rise in value of investment

Explanation:

Capital Gain yield equals the appreciation in an investment's price. It is measured as percentage change over the original investment acquisition value.

Capital Gain Yield = Percentage (%) rise in value of an investment

= ( Rise in Value of Investment / Original Value of investment ) x 100

Eg : If a security purchased for 100 is now for 125 ;

Capital Gain Yield = (25 / 100) x 100

=  25%

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The desired inventory levels of the product.

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The inventory level of a product can be changed or adjusted several times during a year depending on the expected sales. Sometimes very successful products have very seasonal sales, e.g. toys that are sold more on Christmas than any other time of the year.

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1.True

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3 years ago
The town of Pittsford, NY is in need of a new water treatment plant to meet its average daily demand of 18, 000 m3/d and is acce
svlad2 [7]

Answer:

The 1st plant with a storage reservoir is a better option as compared to that of the 2nd plant.

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Suppose the factor for variation in hourly demand is 2 So the average hourly demand is given as

Average Hourly Demand=Factor x Average Daily Demand

AHD=2 x 18000 m3

AHD=36000 m3

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The Quantity in storage tank is 3975 m3

So the amount of pumping required is

Q_{pump1}=AHD-Q_{reservoir}\\Q_{pump1}=36000-3975 \\Q_{pump1}=32025 m^3

For this value the pump will work for following hours

t_{pump1}=\frac{Q_{pump}}{pumping rate_1}\\t_{pump1}=\frac{32025}{1750}\\t_{pump1}=18.3 \, hours

So the pump 1 can complete the demand of the town by working for 18.3 hours.

Now in order to complete the demand, the second pump is given as

Q_{pump2}=AHD\\Q_{pump2}=36000 m^3

For this the pump will work for as

t_{pump2}=\frac{Q_{pump2}}{pumping rate_2}\\t_{pump2}=\frac{36000}{2250}\\t_{pump2}=16 \, hours

So the pump 2 requires 16  hours to complete the demand of the town.

Here it is important to note that the realistic demand of the water can vary from the average value and thus when there is a drastic requirement of water in certain cases, the pump 2 will fail. Also pump 2 has to be run continuously and will produce excessive water which will be wasted if the hourly demand is less than that of the production value.

In context of this, the 1st plant with a storage reservoir is a better option as compared to that of the 2nd plant.

3 0
3 years ago
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