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yuradex [85]
4 years ago
9

When a change of substance occurs, and when solutions are

Chemistry
1 answer:
Yakvenalex [24]4 years ago
8 0

Answer: you are the imposter you killed red then vented in admin

Explanation:

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According to our textbook, write the formula for the anhydrous compound that was part of the mixture called natron that was used
bearhunter [10]

Answer:

The formula for the anhydrous compound that was part of the mixture called natron that was used by the Egyptians is Na2(CO3)10(H2O).

They use this compound for medicine, cookery, agriculture, in glass-making and to dehydrate egyptian mummies.

Compound of sodium carbonate and sodium bicarbonate was the name of the resulting hydrate that formed.

8 0
3 years ago
plz help asap (plz don't give helpless answers) and also ill give brainist to those who answer the questing right
Lera25 [3.4K]
1.) Particle B has a greater kinetic energy because when a particle is at higher temperature it contains more energy.

2.) Diagram B best shows the overflow of heat between the particles. It does because of the enclosed space that it is in and how it will circulate in it.

3.) Heat is transferred between object A and B by having object B (warmer) make a reaction with object A (colder).
5 0
3 years ago
18.0 mL of water contains 6.022 x 1023 water molecules. How many hydrogen atoms are in 1.00 L of water? (Each water molecule, H2
brilliants [131]

Solution :

lt is given that in 18 mL of water their are 6.022\times 10^{23} water molecules.

We know, that 1 molecule of water contains 2 atoms of hydrogen.

Hydrogen atom in 18 mL water is,

2\times 6.022\times 10^{23} = 12.044 \times 10^{23} .

So, number of hydrogen atoms in 1 L = 1000 mL are :

N = \dfrac{1000}{18}\times 12.044\times 10^{23}\\\\N = 6.69 \times 10^{25}\ atoms

Hence, this is the required solution.

3 0
3 years ago
Calculate the number of hydrogen atoms in a sample of hydrazine . Be sure your answer has a unit symbol if necessary, and round
gladu [14]

Answer:

atoms \ H= 9.767x10^{24}atoms

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

7 0
3 years ago
A ball with a density of 1100 kg/m3 is submerged in two liquids: water (ρ = 1000 kg/m3) and honey (ρ = 1400 kg/m3). What will th
Lapatulllka [165]

Hello!

So, we are given a ball with a density of 1100 kg/m³, and two liquids: water (1000 kg/m³) and honey (1400 kg/m³). Our goal is to determine if the ball will sink or float in the given liquids.

Let's take two common substances: water and ice. Water has a density of 1000 kg/m³ and ice has a density of about 917 kg/m³. You would notice that the ice is always floating when you put ice and water together. This would occur if you have other substances.

Here's what you should know:

  1. If the density of an object is greater than the liquid it is in, then that object will sink.
  2. If the density of an object is less than the liquid it is in, then that object will float.

Since the ball has a density of 1100 kg/m³, and water's density is 1000 kg/m³, then the ball will sink. If the ball is placed in honey, then it will float because the density of honey (1400 kg/m³) is greater than the ball's density.

Therefore, objects with a greater density than the surrounding liquid sink, while objects with a smaller density than the surrounding liquid float, which is the fourth choice.

3 0
3 years ago
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