A redox reaction always involves
1 answer:
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Answer:
Check the explanation
Explanation:
As we know the reaction of EDTA and + and EDTA and
+
Let us say that the ratio is 1:1
Therefore, the number of moles of + = molarity * volume
= 0.0400M * 0.011L
= 0.00044 moles
Therefore excess EDTA moles = 0.00044 moles
Given , initial moles of EDTA = 0.0430 M * 0.025 L
= 0.001075
Therefore reacting moles of EDTA with = 0.001075 - 0.00044 = 0.000675 moles
Let us say that the ratio between and EDTA is 1:1
Therefore moles of = 0.000675 moles
Molarity = moles / volume
= 0.000675 moles / 0.057 L
= 0.011 M (answer).
Answer:
Explanation:
M_r: 46.07
C₂H₅OH(ℓ) + 3O₂(g) ⟶ 2CO₂(g) + 3H₂O(ℓ); ΔH = -1418 kJ·mol⁻¹