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Leya [2.2K]
3 years ago
8

How to sovle this equation

Mathematics
2 answers:
professor190 [17]3 years ago
8 0
You could solve all the equations to see if a letter matches the question's request if you're into trail and error. Simply multiply each integer in one pair of parentheses by each individual in another, a box could help you with this (like a box in third grade showing what numbers shown on one side multiplied by numbers on the intersecting side are)

----------------------------------------------------------------------
The answer: If you're looking for the answer, continue below




The answer would be "B";
(x-2)(x^2+2x+4) could be rearranged into..
-2(x^2+2x+4) + x(x^2+2x+4) when, when distributed is..
(-2x^2-4x-8) + (x^3+2x^2+4x) which is then added..
x^3+8

There was some additional simplifying and adding, but you should understand it.
Sonbull [250]3 years ago
7 0

Your answer is b

X^3-8= (x-2)(x^2+2x+4)


To check you multiply each term on first expression to the second expression .


(X-2)(x^2+2x+4)


X(x^2)+x(2x)+x(4) +(-2(x^2)-2(2x)-2(4))


Simplify

X^3+2x^2+4x-2x^2-4x-8


Subtract 2x^2 from 2x^2


X^3+4x+0-4x-8


Add x^3 And 0


X^3+4x-4x-8


Subtract x^3-0


X^3-8


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