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Leya [2.2K]
3 years ago
8

How to sovle this equation

Mathematics
2 answers:
professor190 [17]3 years ago
8 0
You could solve all the equations to see if a letter matches the question's request if you're into trail and error. Simply multiply each integer in one pair of parentheses by each individual in another, a box could help you with this (like a box in third grade showing what numbers shown on one side multiplied by numbers on the intersecting side are)

----------------------------------------------------------------------
The answer: If you're looking for the answer, continue below




The answer would be "B";
(x-2)(x^2+2x+4) could be rearranged into..
-2(x^2+2x+4) + x(x^2+2x+4) when, when distributed is..
(-2x^2-4x-8) + (x^3+2x^2+4x) which is then added..
x^3+8

There was some additional simplifying and adding, but you should understand it.
Sonbull [250]3 years ago
7 0

Your answer is b

X^3-8= (x-2)(x^2+2x+4)


To check you multiply each term on first expression to the second expression .


(X-2)(x^2+2x+4)


X(x^2)+x(2x)+x(4) +(-2(x^2)-2(2x)-2(4))


Simplify

X^3+2x^2+4x-2x^2-4x-8


Subtract 2x^2 from 2x^2


X^3+4x+0-4x-8


Add x^3 And 0


X^3+4x-4x-8


Subtract x^3-0


X^3-8


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Calcule:<br> a)-400-(-700)=
Juliette [100K]

-400-(-700)

-140+700

= 300


I hope that's help ! If you have question(s) please let me know



8 0
3 years ago
I need help please...
telo118 [61]
The answer is b
Area=[pi]r2
= [pi](12 in)2
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7 0
3 years ago
The proportion of students at a college who have GPA higher than 3.5 is 19%. a. You take repeated random samples of size 25 from
melomori [17]

Answer:

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

Step-by-step explanation:

We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=p

\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}

, where p=population proportion and n= sample size.

Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.

i.e. p= 19%=0.19

The for sample size n= 25

The mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785

Hence , the mean and the standard error of the sampling distribution of the sample proportions :

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

8 0
4 years ago
Jaleesa bought two
Korvikt [17]

Answer:

Notebooks= 8.75

computer bags=74.95

Amount with tax = Approximately 89.559

7 0
3 years ago
I don’t know how to find angle A
Cerrena [4.2K]
Angle a = 60

given that all angles of a triangle added together must equal 180
x = -20
-20+80=60
do it again for the other angle measurement
60+60+40=180

therefore, angle A is 60°
5 0
3 years ago
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