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Leya [2.2K]
3 years ago
8

How to sovle this equation

Mathematics
2 answers:
professor190 [17]3 years ago
8 0
You could solve all the equations to see if a letter matches the question's request if you're into trail and error. Simply multiply each integer in one pair of parentheses by each individual in another, a box could help you with this (like a box in third grade showing what numbers shown on one side multiplied by numbers on the intersecting side are)

----------------------------------------------------------------------
The answer: If you're looking for the answer, continue below




The answer would be "B";
(x-2)(x^2+2x+4) could be rearranged into..
-2(x^2+2x+4) + x(x^2+2x+4) when, when distributed is..
(-2x^2-4x-8) + (x^3+2x^2+4x) which is then added..
x^3+8

There was some additional simplifying and adding, but you should understand it.
Sonbull [250]3 years ago
7 0

Your answer is b

X^3-8= (x-2)(x^2+2x+4)


To check you multiply each term on first expression to the second expression .


(X-2)(x^2+2x+4)


X(x^2)+x(2x)+x(4) +(-2(x^2)-2(2x)-2(4))


Simplify

X^3+2x^2+4x-2x^2-4x-8


Subtract 2x^2 from 2x^2


X^3+4x+0-4x-8


Add x^3 And 0


X^3+4x-4x-8


Subtract x^3-0


X^3-8


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mel-nik [20]
Recall your d = rt, distance = rate * time.

now, let's say she lives "d" miles away, and so if Billy goes say at "r" mph fast to her house, he gets there in 1hr.

now, if he goes 20 mph slower, namely " r - 20 " mph, he gets there in 2 hours, same "d" miles.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
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\end{array}
\\\\\\
\begin{cases}
d=r(1)\implies d=\boxed{r}\\
d=2(r-20)\\
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\\\\\\
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4 years ago
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6 0
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