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Anuta_ua [19.1K]
3 years ago
7

Match the reaction on the top with the corresponding reaction on the left. *

Chemistry
1 answer:
BigorU [14]3 years ago
3 0

Answer:

Matching the reaction on the top with the corresponding reaction on the left:

Explanation:

A) 2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(g)

is Electrolysis breaks down water to form hydrogen and oxygen gas

B) 2H2(g) + O2(g) = 2H2O(g)

is

A bright light is produced when magnesium reacts with the oxygen in air to form magnesium oxide

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What is the maximum number of grams of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl
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<u>Answer:</u> The maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

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Putting values in above equation, we get:

0.167M=\frac{\text{Moles of p-toluidine hydrochloride}\times 1000}{70}\\\\\text{Moles of p-toluidine hydrochloride}=\frac{0.167\times 70}{1000}=0.0117mol

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\text{p-toluidine hydrochloride}+\text{Acetic anhydride}\rightarrow \text{N-acetyl-p-toluidine}

By Stoichiometry of the reaction:

1 mole of p-toluidine hydrochloride produces 1 mole of N-acetyl-p-toluidine

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To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of N-acetyl-p-toluidine = 149.2 g/mol

Moles of N-acetyl-p-toluidine = 0.0117 moles

Putting values in equation 1, we get:

0.0117mol=\frac{\text{Mass of N-acetyl-p-toluidine}}{149.2g/mol}\\\\\text{Mass of N-acetyl-p-toluidine}=(0.0117g/mol\times 149.2)=1.7g

Hence, the maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

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