Question

Calcium oxide (CaO), an important ingredient in cement, is produced by decomposing calcium carbonate (CaCO3) at high temperature: CaCO3(s) → CaO(s) + CO2(g) In one particular reaction, 25 g of CaCO3 is heated at 550°C in a 5.0 L vessel. The pressure of CO2 is 0.25 atm after 10.0 minutes. What is the average rate of CO2 production in moles per minute during the 10 minutes? (Enter in mol/min.)

Answer 1

Answer:

0.0018 mol/min is the average rate of carbon dioxide gas production in moles per minute during the 10 minutes.

Explanation:

Pressure of carbon dioxide gas = P = 0.25 atm

Volume of carbon dioxide gas = V = 5.0 L

Moles of carbon dioxide gas = n

Temperature of the carbon dioxide gas,T = 550°C = 550+273 K = 823 K

Using an ideal gas equation :

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.25 atm\times 5.0 L}{0.0821 atm L/mol K\times 823 K}$

n = 0.018 mol

In 10 minutes pressure of carbon dioxide gas reached to 0.25 atm

Average rate of production of moles of carbon dioxide gas per minute in duration of 10 minutes:

$=\frac{0.018 mol}{10 min}=0.0018 mol/min$

0.0018 mol/min is the average rate of carbon dioxide gas production in moles per minute during the 10 minutes.