The formula is m = D x V
D = <span>13.69 g/cm^3.
</span>V = <span>15.0 cm^3
the mass of the liquid mercury is m= </span>13.69 g/cm^3 x 15.0 cm^3 = 195g
the molar mass of Hg is 200,
1 mole of Hg = 200g Hg, so #mole of Hg= 195 / 200 = 0.97 mol
but we know that
1 mole = 6.022 E23 atoms
0.97 mole=?
6.022 E23 atoms x 0.97 / 1 mole = 5.84 E23 atoms
At constant temperature and pressure, the change in Gibbs free energy is defined as DG= DH-TDS hope this helps bb ♡
The element aluminum forms a cation with the charge of +3. The symbol for this ion is Al³⁺, and the name is aluminum ion. The number of electrons in this ion 10.
<h3>What are ions?</h3>
Ions are formed when an atom gains or loses electrons.
Metals form positive ions by a loss of electrons whereas non-metals form negative ions by gaining electrons.
The aluminum ion is formed when aluminum loses three electrons to form Al³⁺ ion which has 10 electrons.
in conclusion, ions are formed by a gain or loss of electrons.
Learn more about ions at: brainly.com/question/490569
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Answer:
B. hexane
Explanation:
Im not sure I just goggled it
Answer:
- 50.7 kJ.
Explanation:
- To get the enthalpy change for the reaction:
Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).
- We must orient the given reactions in a way that its sum give the required reaction.
The first reaction be as it is:
Mn₃O₄(s) + 4CO(g) ⟶ 3Mn(s) + 4CO₂(g), <em>ΔH₁ = 255.6 kJ.</em>
The second reaction should be reversed and multiplied by 3 and also the value of its ΔH must multiplied by (- 3):
3Mn(s) + 3CO₂(g) ⟶ 3MnO(s) + 3CO(g), <em>ΔH₂ = (- 3)(102.1 kJ) = - 306.3 kJ.</em>
- By summing the two reactions after the modification, we get the required reaction:
<em>Mn₃O₄(s) + CO(g) ⟶ 3MnO(s) + CO₂(g).</em>
<em></em>
<em>∴ ΔH rxn = ΔH₁ + ΔH₂ = (255.6 kJ) + (- 306.3 kJ) = - 50.7 kJ.</em>