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Mashutka [201]
3 years ago
13

wo competing gyms each offer childcare while pareTnts work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 p

er 5 minutes of childcare. Which comparison of the childcare costs is accurate? Gym B charges $1.05 less per hour than Gym A. Gym B charges $1.50 less per hour than Gym A. Gym B charges $5.25 less per hour than Gym A. Gym B and Gym A charge the same hourly rate for childcare.
Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:

gym a has the better sale.

Step-by-step explanation:


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Expand: In 2a3/b4<br> In 2 + 3 In a - 4 In b<br> In 2 - 3 In a - 4 In b<br> In 2-3 In a + 4 In b
weqwewe [10]

Answer:

ln(2) + 3ln(a) - 4ln (b)

Step-by-step explanation:

ln(2a^3 /b^4)

We know that ln(x/y) = ln (x) - ln y

ln(2a^3 ) - ln (b^4)

We know that ln (xy) = ln x + ln y

ln(2) + ln(a^3 ) - ln (b^4)

We know that ln(x^y) = y ln (x)

ln(2) + 3ln(a) - 4ln (b)

8 0
3 years ago
40 kg to 32 kg as a fraction
user100 [1]
<h2>72 kg</h2>

hope it helps you

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8 0
3 years ago
Read 2 more answers
Identify the terms, like terms, coefficients, and constants in each expression.
steposvetlana [31]
Simplifying
8 + 6t = 3t + t

Combine like terms: 3t + t = 4t
8 + 6t = 4t

Solving
8 + 6t = 4t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-4t' to each side of the equation.
8 + 6t + -4t = 4t + -4t

Combine like terms: 6t + -4t = 2t
8 + 2t = 4t + -4t

Combine like terms: 4t + -4t = 0
8 + 2t = 0

Add '-8' to each side of the equation.
8 + -8 + 2t = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 2t = 0 + -8
2t = 0 + -8

Combine like terms: 0 + -8 = -8
2t = -8

Divide each side by '2'.
t = -4

Simplifying
t = -4
8 0
3 years ago
Plz Help I would appreciate it!!!
andrew-mc [135]

Answer:

a) Similar triangles are triangles with the same shape but not necessarily the same size

b) 15/45 = 8/x

1/3 = 8/x (simplify the 15/45)

x = 8 * 3 (cross multiplication)

x = 24

c) y^2 = 15^2 + 8^2 (Pythagoras theorem)

y = *square root of* 15^2 + 8^2

y = 17

1/3 = 17/z

z = 17 * 3 (cross multiplication)

z = 51

6 0
3 years ago
Solve x^2 – 8x + 41 = 0 for x.
icang [17]
<span>\displaystyle x^2 - 8x + 41 = 0 \\\\ \Delta=b^2-4ac \\ \Delta=(-8)^2-4\cdot1\cdot41 \\ \Delta=64-164 \\ \Delta=-100 \\ \\ X_{1,2}= \frac{-b\pm i \sqrt{-\Delta} }{2a} = \frac{8 \pm 10i}{2} \\ \\ X1=4-5i \\ \\ X2=4+5i</span>
5 0
3 years ago
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