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Valentin [98]
4 years ago
8

What is 14 2/3 divided by 2 3/4

Mathematics
2 answers:
masya89 [10]4 years ago
3 0
5.3 repeating, I believe.
KengaRu [80]4 years ago
3 0
14*2/3 is 9.3 and 2 * 3/4 is 1.5
9.3/1.5 is 6.2
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The lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of
valina [46]

Answer:

(221.39, 300.61) and (255.2223, 266.7777)

Step-by-step explanation:

Given that X, the  lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days

Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0

Corresponding we have x scores as

Between 261-2.33*17 and 261+2.33*17

i.e. in the interval = (221.39, 300.61)

If sample size = 47, then std error of sample would be

\frac{17}{\sqrt{47} }

So 98% of pregnancies would lie between

261-2.33*\frac{17}{\sqrt{47} } and 262+2.33*\frac{17}{\sqrt{47} }

= (255.2223, 266.7777)

8 0
3 years ago
Katie is 6/10 of the way to Brianna's house. Larry is 7/10 of the way to Brianna's house. How much closer to Brianna''s house is
SVETLANKA909090 [29]
I think Larry is 1/10 closer to Brianna's than Katie.
3 0
3 years ago
There were 5 people who bought
Fudgin [204]
15 tickets in all 5x3
7 0
4 years ago
Read 2 more answers
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
Forest habitat is cleared to build a new shopping complex. what does this scenario represent? a loss of biodiversity due to a cl
Dominik [7]

A loss of biodiversity due to human activity.

8 0
2 years ago
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