Explanation:
Entropy is defined as the degree of randomness present in a substance. Therefore, more is the irregularity present in a compound more will be its molar entropy.
Hence, decreasing order to molar entropy in state of matter is as follows.
Gases > Liquids > Solids
- In the first pair, we are given
or 
. Since, molar entropy of liquids is less than the molar entropy of gases.
Hence, will have larger molar entropy as compared to .
- In the second pair, we are given Fe(s) or Ni(s). More is the molar mass of a compound more will its molar entropy. Molar mass of Fe is 55.84 g/mol and molar mass of Ni is 58.69 g/mol.
Hence, molar entropy of Ni(s) is more than the molar entropy of Fe(s).
- In the third pair, we are given
or 
. As both the given species are gaseous in nature. So, more is the molar mass of specie more will be its molar entropy.
Molar mass of is 30.07 g/mol and molar mass of is 28.05 g/mol. Therefore, molar entropy of is more than the molar entropy of .
- In the fourth pair, we are given
or 
. Molar mass of is 153.82 g/mol and molar mass of is 16.04 g/mol.
Therefore, molar entropy of is more than the molar entropy of .
- In the fifth pair, we are given HgO(s) or MgO(s). Molar mass of HgO is 216.59 g/mol and molar mass of MgO is 40.30 g/mol.
Hence, molar entropy of HgO(s) is more than the molar entropy of MgO.
- In the fifth pair, we are given NaCl(aq) or
. Molar mass of NaCl 58.44 g/mol and molar mass of is 95.21 g/mol.
Hence, the molar entropy of is more than the molar entropy of NaCl(aq).
Answer:
= 200 mL
Explanation:
Using the dilution formula;
M1V1 = M2V2 ;
Where, M1 is the concentration before dilution, V2 is the volume before dilution, while M2 is the concentration after dilution and V2 is the volume after dilution.
M1 = 2.0 M
V1 = 50 mL
M2 = 0.50 M
V2 = ?
V2 = M1V1/M2
= ( 2.0 × 50 )/ 0.5
= 200 mL
Therefore, the volume after dilution will be, 200 mL
Answer:
oK so pay pattention to the fractions
Explanation:
