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3 years ago

A partir de lo propuesto por Bohr en 1913, que postulado es correcto:

Chemistry

1 answer:

TEA [102]3 years ago

4 0

Answer:

Primer postulado:

Así Bohr asumió que el átomo de hidrógeno puede existir solo en ciertos estados discretos, los cuales son denominados estados estacionarios del átomo. En el átomo no hay emisión de radiación electromagnética mientras el electrón no cambia de órbita.

Explanation:

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The breakdown of dopamine is catalyzed by the enzyme monoamine oxidase (MAO). What is the final concentration of product if the

kotegsom [21]

Answer:

final concentration: Ca = 0.014 M

Explanation:

Velocity of reaction:

ra = K(Ca)∧α = δCa/δt

∴ α: order of reaction, assuming α = 1

∴ K = 0.249 s-1.......rate constant

∴ Cao = 0.050 M......initial concentration

∴ t = 5 s.......reaction time

⇒ δCa/δt = K*Ca

⇒ ∫δCa/Ca = K*∫δt

⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245

⇒ Cao/Ca = 3.473

⇒ Ca = 0.050/3.473

⇒ Ca = 0.014 M

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dybincka [34]

Esters contains a double bond between carbon atom and oxygen atom while carboxylic acid lack double bond between carbon and oxygen atom.The lack of double bond in carboxylic acid make the force of interaction between carbon and oxygen strong and particles become tightly packed which make carboxylic acid solid. The presence of double bond in esters make the force of interaction weak thus they are liquid.

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Which is the following describes a solution?

Dvinal [7]

A solution is uniform throughout, so your answer is the first one.

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Half of the earth is in the light and the other half is in the shadow because

Elza [17]

Answer:

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Explanation:

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2 years ago

Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions: hso4−+h2o⇌so42−+h3o+ identify the conjugate acid-

Angelina_Jolie [31]

The generic equation for a reaction between an acid and water is

$HX_{(aq)} + H_{2}O_{(aq)} --> X_{(aq)}^{-} + H_{3}O_{(aq)}^+$

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base ( $X^-$ ), and the conjugate acid-base pair is $HX$ - $X^-$ .

Hydrogen sulfate ( $HSO_{4}^-$ ) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water (( $H_{2}O$ ) to form the sulfate ( $SO_{4}^2-$ ) and hydronium ( $H_{3}O^+$ )ions.

$HSO_{4(aq)}^{-} + H_{2}O_{(aq)} --> SO_{4(aq)}^{2-} + H_{3}O_{(aq)}^+$

Based on the previous discussion, $SO_{4(aq)}^2-$ is identified to be the conjugate of the acid $HSO_{4(aq)}^-$ . Thus, the conjugate acid-base pair is $HSO_{4(aq)}^{-} - SO_{4(aq)}^{2-}$ .

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3 years ago