Answer : Volume of HCl ( in ml) is 10 ml.
Solution : Given, Concentration of NaOH = 0.1 mol/L
Volume of NaOH = 20 ml
Concentration of HCl = 0.2 mol/L
Volume of HCl = ?
Formula used : Moles = Volume × Concentration
In the reaction, we see that 1 mole of NaOH react with the 1 mole of HCl.
so,
Moles of NaOH = Moles of HCl
Moles of HCl = Moles of NaOH = Volume of NaOH ( in L) × Concentration of NaOH
Converstion ml into L : 1000 ml = 1 L
Moles of HCl = 
× 0.1
= 0.002 mol
Volume of HCl = Moles / Comcentration of HCl
= 
= 0.01 L
Volume of HCl (in ml) = 0.01 × 1000 = 10 ml
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Using the Michaelis-Menten equation competitive inhibition, the Inhibition constant, Ki of the inhibitor is 53.4 μM.
<h3>What is the Ki for the inhibitor?</h3>
The Ki of an inhibitor is known as the inhibition constant.
The inhibition is a competitive inhibition as the Vmax is unchanged but Km changes.
Using the Michaelis-Menten equation for inhibition:
Making Ki subject of the formula:
where:
- Kma is the apparent Km due to inhibitor
- Km is the Km of the enzyme-catalyzed reaction
- [I] is the concentration of the inhibitor
Solving for Ki:
where
[I] = 26.7 μM
Km = 1.0
Kma = (150% × 1 ) + 1 = 2.5
Ki = 26.7 μM/{(2.5/1) - 1)
Ki = 53.4 μM
Therefore, the Inhibition constant, Ki of the inhibitor is 53.4 μM.
Learn more about enzyme inhibition at: brainly.com/question/13618533
