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Pepsi [2]
2 years ago
11

In the tropical rainforests, birds have evolved to eat the brightly-colored fruits. The fruits have evolved their attractive col

or so the birds will eat them and spread their seed. What theory is this an example of? A artificial selection b coevolution c mutation d natural selection
Chemistry
1 answer:
Reika [66]2 years ago
3 0

Answer:

coevolution

Explanation:

Coevolution plays a key role in shaping the biodiversity on Earth. Coevolution is commonly defined as reciprocal evolutionary changes brought about by interactions between species, implying that interacting species impose selection on each other(Science direct).

We can see that the change that occurred in the plants of the tropical rainforests is closely related to their link to birds. The fruits evolved an attractive color so that birds, having evolved to eat the brightly-colored fruits, may eat them.

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Answer:

In order to rinse the system of exhaled CO2 and meet the inspiratory flow rate requirements of infants placed on B-CPAP, the flow rate of humidified gas should be set at:

A. 16 to 20 L/minute

B. 6 to10 L/minute

C. at least 15 L/minute

D. 11 to 15 L/minute

B. 6 to10 L/minute

Explanation:

Bubble CPAP is a non-invasive, external ventilation technique used for newborn babies with infant respiratory distress syndrome (IRDS). Continuous positive airway pressure (CPAP) is given to a spontaneously breathing newborn baby to preserve lung volumes during expiration

3 0
3 years ago
A student weighs out a 6.64 g sample of , transfers it to a 500. mL volumetric flask, adds enough water to dissolve it and then
Vsevolod [243]

Answer:

the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

Explanation:

Given that :

a student dissolves 6.64 g of CoF₂  into 500 mL of water

volume of the solution(water) = 500 mL = 0.50 L

The standard  molar mass of CoF₂ is 96.93 g/mol

number of moles of CoF₂ = mass of CoF₂/molar mass of CoF₂

number of moles of CoF₂ = 6.64 g/96.93 g/mol

number of moles of CoF₂ = 0.0685 mol

The molarity of any given substance is known to be as the number of moles of solute dissolved in one litre of solution.

Thus ;

Molarity of  cobalt(II) fluoride CoF₂ in the resulting solution is = number of moles / Volume in (L)

Molarity of  cobalt(II) fluoride CoF₂  = 0.0685 mol/ 0.50 L

= 0.137  M

Thus ; the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

7 0
2 years ago
Balance the reaction ____Mo+___O2> ___MoO3​
DIA [1.3K]

The balanced reaction is: 2Mo+3O2>2MoO3

7 0
2 years ago
Nickel carbonyl, Ni(CO)4 is one of the most toxic substances known. The present maximum allowable concentration in laboratory ai
vodomira [7]

<u>Answer:</u> The mass of Ni(CO)_4 allowable in the laboratory is 4599.5 grams

<u>Explanation:</u>

To calculate the volume of cuboid, we use the equation:

V=l\times b\times h

where,

V = volume of cuboid

l = length of cuboid = 14 ft

b = breadth of cuboid = 22 ft

h = height of cuboid = 9 ft

Putting values in above equation, we get:

V=14\times 22\times 9=2772ft^3=78503.04L     (Conversion factor:  1ft^3=28.32L

To calculate the moles of gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 78503.04 L

T = Temperature of the gas = 23^oC=[23+273]K=296K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

1.00atm\times 78503.04L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 296K\\\\n=\frac{1.00\times 78503.04}{0.0821\times 296}=3230.4mol

Applying unitary method:

For every 109 moles of gas, the moles of Ni(CO)_4 present are 1 moles

So, for 3230.4 moles of gas, the moles of Ni(CO)_4 present will be = \frac{1}{109}\times 3230.4=26.94mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Ni(CO)_4 = 26.94 moles

Molar mass of Ni(CO)_4 = 170.73 g/mol

Putting values in above equation, we get:

26.94mol=\frac{\text{Mass of }Ni(CO)_4}{170.73g/mol}\\\\\text{Mass of }Ni(CO)_4=(26.94mol\times 170.73g/mol)=4599.5g

Hence, the mass of Ni(CO)_4 allowable in the laboratory is 4599.5 grams

3 0
3 years ago
3. What are transition metals?
brilliants [131]

Answer:

to

Explanation:

7 0
2 years ago
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