<span>12.7 g Li*(1 mole Li/6.94 g Li)=1.83 moles of Li
34.7 g N2(1 mole N2/28 g N2)=1.23
1.83 moles Li*(2 moles Li3N/6 mole Li)(34.82 grams Li3N/1 mole Li3N)=21.24g Li3N </span>
The answer is: the rate of reaction is 850 g/min.
n(P₄O₁₀) = 1.5 mol; amount of product.
M(P₄O₁₀) = 283.9 g/mol; molar mass of phosphorus(V) oxide.
m(P₄O₁₀) = n(P₄O₁₀) · M(P₄O₁₀).
m(P₄O₁₀) = 1.5 mol · 283.9 g/mol.
m(P₄O₁₀) = 425.85 g in 30 seconds.
Make proportion: 425 g : 30 s = m(P₄O₁₀) : 60 s.
m(P₄O₁₀) = 850 g in 60 s.
Answer: 65.38g of Ca(OH)2 is needed
Explanation:
From The equation of reaction
2 HCl + Ca ( OH ) 2 ⟶ CaCl 2 + 2 H 2 O
NB: Molar mass of HCl= 1+35.5=36.5
Ca(OH)2= 74
From The stoichiometric equation
2mol of HCl(36.5×2=73) require 1mol of Ca(OH)2 (74g)
Hence 64.5g of HCl will require 64.5×74/73= 65.38g of Ca(OH)2
