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prohojiy [21]
3 years ago
13

15x + 3 + 2x + 9r - (8 - r)

Mathematics
1 answer:
bezimeni [28]3 years ago
6 0

Answer:

17x + 10r -5

Step-by-step explanation:

15x +3 + 2x + 9r- (8-r)

17x +3 +9r -8 +r

17x+ 10r+ -5

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What is the solution of the equation w/4 +3= w/3
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Answer:

52

Step-by-step explanation:

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Ms. Chang has 16 students in her class. She wants to send 3 of her students to pick up books for the class. How many combination
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At total of 2 feet of snow falls over three days on the first day 1/6 of the snow falls on the second day 7/12 of the snow falls
ioda

Answer:

Day\ 3 = 1\frac{3}{12}

Step-by-step explanation:

Given

Total = 2ft

Day\ 1 = \frac{1}{6}

Day\ 2 = \frac{7}{12}

Required

Determine the amount of snow on day 3

This can be calculated using:

Day\ 1 + Day\ 2 + Day\ 3 = Total

Substitute values for the known parameters

\frac{1}{6} + \frac{7}{12} + Day\ 3 = 2

Collect Like Terms

Day\ 3 = 2 - \frac{1}{6} - \frac{7}{12}

Take LCM

Day\ 3 = \frac{24 - 2 - 7}{12}

Day\ 3 = \frac{15}{12}

Express as mixed number

Day\ 3 = 1\frac{3}{12}

5 0
3 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0&lt;=t&lt;=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
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