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3 years ago

15x + 3 + 2x + 9r - (8 - r)

Mathematics

1 answer:

bezimeni [28]3 years ago

6 0

Answer:

17x + 10r -5

Step-by-step explanation:

15x +3 + 2x + 9r- (8-r)

17x +3 +9r -8 +r

17x+ 10r+ -5

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2 years ago

Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!

sergeinik [125]

Answer:

a). 8(x + a)

b). 8(h + 2x)

Step-by-step explanation:

a). Given function is, f(x) = 8x²

For x = a,

f(a) = 8a²

Now substitute these values in the expression,

$\frac{f(x)-f(a)}{x-a}$ = $\frac{8x^2-8a^2}{x-a}$

= $\frac{8(x^2-a^2)}{(x-a)}$

= $\frac{8(x-a)(x+a)}{(x-a)}$

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b). $\frac{f(x+h)-f(x)}{h}$ = $\frac{8(x+h)^2-8x^2}{h}$

= $\frac{8(x^2+h^2+2xh)-8x^2}{h}$

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4 0

3 years ago

Tamika built a large play area in the shape of a rectangle. The length of one side was 8 meters, and the length of the other sid

ryzh [129]

The dimensions of the rectangle given are

length = 14 meters

Width = 8 meters

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The rectangle has to opposite sides of 14 meters and two opposite sides of 8 meters

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3 years ago

Read 2 more answers

What is the other square root of 119 + 120i?

MakcuM [25]

Answer:

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

Step-by-step explanation:

Given

z = 119 + 120 i

Let $\sqrt{119+120 i}=p+iq$

Squaring both sides

$119+120 i=p^2-q^2+2ipq$

Comparing real and imaginary part

Re(LHS)=Re(RHS)

$119=p^2-q^2$ ...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

$q=\frac{60}{p}$

Substitute q in 1

$119=p^2-(\frac{60}{p})^2$

$p^4-119p^2-(68)^2=0$

Let $x=p^2$

$x^2-119x-4624=0$

$x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}$

$x=\frac{119\pm 180.71}{2}$

we take only Positive value because $p^2=x$

x=149.85

$p^2=149.85$

thus $p=\pm 12.24$

$q=\pm 4.90$

thus,

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

8 0

3 years ago