Question

Create an equation that has exactly one real solution. 6(3x+4)-x=_x+3

Answer 1

Answer:

$x(x+5)=x^2-3x+8$

Step-by-step explanation:

There are infinite cases of equations with exactly one real solution. To create something worth the space, this one should suffice

$x(x+5)=x^2-3x+8$

Operating

$x^2+5x=x^2-3x+8$

Simplifying

$5x=-3x+8$

Joining like terms

$8x=8$

Solving

x=1

Testing the result

$1(1+5)=1^2-3(1)+8=>6=6$