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3 years ago

Which of the following integers is a perfect square? A 36 B 48 C 44 D 32

Mathematics

2 answers:

Anika [276]3 years ago

5 0

Answer:

Step-by-step explanation:

since 36=6² and the other option is not square of integer

Viktor [21]3 years ago

3 0

Answer:A) 36

Step-by-step explanation: 36 is the only number that can be square rooted into a whole number.

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Alex

$(-12x^3 yz)(-4x^3yz^4)\\\\=48x^6y^2 z^5$

3 0

2 years ago

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The function h(x) is a transformation of the square root parent function,

kondaur [170]

Answer:

A. $h(x)=\sqrt{x-3}$

Step-by-step explanation:

<h3>Step 1: Definition</h3>

The parent function of $\sqrt{x}$ is translated to the left when $h$ is positive in the transformation $\sqrt{x+h}$ .

If $h$ is negative, the graph translates towards the left with the distance equal to the value of $h$ .

<h3>Step 2: Implementation</h3>

Here the graph moved 3 units towards the right. This means that $h$ is negative and has the value of 3.

So, plugging that into the parent function for translation, the function becomes:

$h(x)=\sqrt{x-3}$

8 0

2 years ago

Can someone help me and explain? I will mark brainlest. ♡

Sedbober [7]

Answer:

$p'(4) = -3$

$q'(8) = \frac{1}{4}\\$

Step-by-step explanation:

For p'(4):

$p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)$

$p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3$

For q'(8):

$q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}$

$q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}$

4 0

3 years ago

Read 2 more answers

Factor completely 2x^3y^4-8x^2y^3+6xy^2

Maru [420]

Answer:

2 x y^2 (x y - 1) (x y - 3)

Step-by-step explanation:

2x^3y^4-8x^2y^3+6xy^2

each term contains 2xy^2 so factor that out

2xy^2(x^2y^2 -4xy+3)

then lets factor the inside

what terms multiply together to give us +3 and add to -4

-3* -1 = 3 -3+-1 =-4

2 x y^2 (x y - 1) (x y - 3)

6 0

3 years ago

How do you write 8.07 x 10 ^-3 in standard form?

Vlad [161]

Standard Form would be 0.00807

5 0

3 years ago