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3 years ago

How can you balance this chemical equation?HSiCl3+H2O~H10Si10O15+HCL

Chemistry

1 answer:

qwelly [4]3 years ago

4 0

10HSiCl3 + 15H2O = H10Si10O15 + 30HCl

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A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

3 years ago

Which statement describes what happens to the DNA in the process shown? A. Some of the DNA is destroyed, so each daughter cell h

kolbaska11 [484]

hhjjjbvhjbvb

hhmkn

hjkk

hhjj

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3 years ago

Question 4

ruslelena [56]

Answer:

Physical change

Explanation:

Brainliest would be appreciated

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3 years ago

A 222 N force is required to keep an object moving along a circular path with a diameter of 11.6 m at a speed of 7.60 m/s. What

Arte-miy333 [17]

Answer:

$m=22.3\ kg$

Explanation:

The expression for centrifugal force is shown below as:-

$F=\frac{m\times v^2}{r}$

Where, m is the mass of the object = ?

v is the velocity of the object = 7.60 m/s

r is the radius

F is the force = 222 N

Diamter = 11.6 m

Radius = d/2 = 11.6 m/2 = 5.8 m

Applying the values in the above expression as:-

$222=\frac{m\times {7.60}^2}{5.8}$

$57.76m=1287.6$

$m=22.3\ kg$

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3 years ago

Which of the following is an example of a transuranium element

ella [17]

Elements with atomic number greater than 92(Atomic number of Uranium) are known as transuranium element.

Cm - Curium is a transuranium element as its atomic number is 96.

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3 years ago

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How can you balance this chemical equation?HSiCl3+H2O~H10Si10O15+HCL​

How can you balance this chemical equation?HSiCl3+H2O~H10Si10O15+HCL