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4 years ago

What is the molarity of a solution in which 0.732 moles of hcl are dissolved in 0.975 liters of solution?

Chemistry

1 answer:

posledela4 years ago

6 0

Molarity is moles divided by liters so do .732 divided by .975 liters.

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kondaur [170]

Answer:

C. The hand shears because their shorter handles transfer force more quickly to the cutting blade.

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3 years ago

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Terry heats two different masses of substance A to different temperatures, and measures the amounts of both carbon dioxide and w

Naddika [18.5K]

Answer:

This experiment is uncontrolled because two different masses of substance A are used.

Explanation:

A controlled experiment is a structured experiment aimed at testing a particular observation or observations. The setup of a controlled experiment helps to determine the reason why a particular observation occurs and what must have led to it.

In the experiment highlighted above, different masses of a substance were used, they were heated to different temperatures. The set up does not show any correlation between the masses of substances heated and the temperatures. It is even difficult to try to predict the hypothesis for this kind of experimental set up. All the variables in play can best be assumed to be independent of one another.

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3 years ago

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In all states of matter, atoms of all elements A. bind together the same way. B. are in constant motion. C. are the same size. D

kolezko [41]

B: Are in constant motion

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4 years ago

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67.3 inches to meters

Drupady [299]

Answer: 1.70942

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3 years ago

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Calculate the specific heat capacity for a 22.7-g sample of lead that absorbs 237 J when its temperature increases from 29.8 °C

soldier1979 [14.2K]

Answer:

$\boxed {\boxed {\sf c\approx 0.159 \ J/ g \textdegree C}}$

Explanation:

We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

$c= \frac{Q}{m \times \Delta T}$

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases from 29.8 °C to 95.6 °C.

ΔT = final temperature -inital temperature
ΔT= 95.6 °C - 29.8 °C = 65.8 °C

Now we know all three variables and can substitute them into the formula.

Q= 237 J
m= 22.7 g
ΔT = 65.8 °C

$c= \frac {237 \ J}{22.7 \ g \ \times \ 65.8 \textdegree C}$

Solve the denominator.

22.7 g * 65.8 °C = 1493.66 g °C

$c= \frac {237 \ J}{1493.66 \ g \textdegree C}$

Divide.

$c= 0.1586706479 J /g \textdegree C$

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

$c \approx 0.159 \ J/g \textdegree C$

The specific heat capacity of lead is approximately 0.159 Joules per gram degree Celsius.

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3 years ago