Yes there is actually a formula for this. This is an arithmetic progression with a common difference of 1.
The sum of terms can be solved by using the formula
S = (n/2) * (a1 + an)
where S is the sum of the terms
n is the number of terms
a1 is the first term
an is the last term
we can calculate the number of terms, n by using the formula
an = a1 + (n-1)*d
d is the common difference equal to 1
therefore n = 51
substituting to the first equation
S = 2805
Answer:
36 Teachers in Total
Step-by-step explanation:
I would use Ratio.
Students: 128 + 121 + 135 = 384 total students
Teachers: Students
3 : 32
36 : 384
384 ÷ 32 = 12
12 x 3 = 36
Answer:
(x+3)(x+4)(x-4)
x+2 and x-3 are not factors but x-4 is
Step-by-step explanation:
let's factor it :)
x^3 + 3x^2 - 16x -48
first we will factor this:
x^3 + 3x^2
x^2(x + 3)
then factor the second part :
- 16x - 48
-16(x + 3)
so now,
x^2(x + 3) - 16(x + 3)
factor out x+3
(x+3)(x^2 - 16)
factor x^2 - 16
(x+3)(x+4)(x-4)
Answer:
eight
Step-by-step explanation:
76 / 100 = 0.76 , 0.76 x 45 = 34.2
