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Vsevolod [243]
3 years ago
5

The scale of a map uses 10 cm for 30 km. How many centimeters does it use for 9 km? +

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0

Answer:

3 km

Step-by-step explanation:

30 divided by 10 is 3.

9 divided by 3 is 3.

Therefore, your answer is 3.

You might be interested in
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Find the domain of the following relation. <br> R={(19,96),(20,101),(21,106),(22,111)}
mafiozo [28]
(x, y)

The domain are all the x-values, the range are all the y-values.

R={(19,96),(20,101),(21,106),(22,111)}

The domain is: 19, 20, 21, and 22
The range is: 96, 101, 106, and 111
7 0
3 years ago
Read 2 more answers
Question 5 (10 points)
Kamila [148]
You have to subtract 4.35 from 15.60 to see for all the children
3x+4.35 = 15.60
5 0
2 years ago
A ball is dropped from a height of 600 feet. The function describing the height of the ball at t seconds after it dropped is <im
bekas [8.4K]

The average velocity of the object after during the first three seconds is: 48m/s

The time at which the instantaneous velocity equals the average velocity within the first three seconds is 1.5 seconds.

<h3>What is instantaneous and average velocities?</h3>

Instantaneous velocity  is the speed of an object at a particular point in time.

Average velocity is the velocity of an object after covering a certain distance for a period of time

Analysis:

Given

initial height = 600 feet

Height with respect to time = f(t) = -16t^{2} + 600

a) Height at t = 0 = 600 feet

    Height at t = 3 seconds = f(3) = -16(3)^{2} + 600 = 456 feet

Distance travelled  = 600 - 456 = 144 feet

Average velocity = distance travelled/time taken  = 144/3 = 48 feet/seconds

b) instantaneous velocity at time t = \frac{df(t)}{dt} = \frac{d(-16t^{2} + 600) }{dt} = -32t

  when instantaneous velocity equal average velocity

     -32t = -48

      t = 1.5 seconds

In conclusion, the Average velocity after 3 seconds is 48 feet per seconds and the time taken for the average velocity to equal the instantaneous velocity is 1.5 seconds.

Learn more about instantaneous and Average velocity: brainly.com/question/13372043

#SPJ1

7 0
2 years ago
koda Buys 0.75 kg of cortos,which ia 5times the mas of the union he also Buys. How much does the union weigh?
kari74 [83]

Answer:

0.15kg

Step-by-step explanation:

Given data

We are told that

0.75 kg of cortos weights 5times the mas of the onion

We want to find the mass of 1 onion

Hence

0.75 kgcortos = 5 onions

      x cortos = 1 onions

x= 0.75/5

x= 0.15kg

Hence 1 onion will weigh 0.15kg

4 0
3 years ago
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