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Anuta_ua [19.1K]
3 years ago
8

Solve screen shot attachment EASY

Mathematics
1 answer:
Leona [35]3 years ago
8 0

Answer:

x = \frac{-3d-9}{k-d}

Step-by-step explanation:

Step 1: Write out equation

d(-3 + x) = kx + 9

Step 2: Distribute <em>d</em>

-3d + dx = kx + 9

Step 3: Subtract 9 on both sides

-3d + dx - 9 = kx

Step 4: Subtract dx on both sides

-3d - 9 = kx - dx

Step 5: Factor out <em>x</em>

-3d - 9 = x(k - d)

Step 6: Divide both sides by k - d

x = \frac{-3d-9}{k-d}

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Using the difference of squares rule, we can say
g^2 - 9 = g^2 - 3^2
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<span>So, the answer is (g-3)(g+3). This is the same as (g+3)(g-3)</span>

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The product of the given expression is \rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs.

Given

The product of \rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2.

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of \rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2 is given by;

\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2\\\\(2r^3 + 2r^2s) + 2rs + 2rs + 2rs + s^2r^2 + sr^2 + 2s^2\\\\2r^3+ 2r^2s + 6rs + s^2r^2 + sr^2+ 2s^2

\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs

Hence, the product of the given expression is \rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs.

To know more about Multiplication click the link given below.

brainly.com/question/19943359

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Answer:

could you explain further

Step-by-step explanation:

i dont understand

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