Actually the position function with respect to time under constant acceleration is:
a=g
v=⌠g dt
v=gt+vi
s=⌠v
s=gt^2/2+vit+si
So if vi and si are zero then you just have:
s=gt^2/2
Notice that it is not gt^2 but (g/2) t^2
So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...
Anyway....
sf=(a/2)t^2+vit+si
(sf-si)-vit=a(t^2)/2
2(sf-si)-2vit=at^2
a=(2(sf-si)-2vit)/t^2 and if si and vi equal zero
a=(2s)/t^2
Answer:
no solution
Step-by-step explanation:
6x - 3y = 7 → (1)
- 2x + y = - 8 → (2)
multiplying (2) by 3 and adding to (1) eliminates the variables
- 6x + 3y = - 24 → (3)
add (1) and (3) term by term
0 + 0 = - 17
0 = - 17 ← false statement
This indicates the system has no solution
Answer:
90°
Step-by-step explanation:
right angle - 90°
.....
1. being destroyed would be a negative number
2. water increasing in temperature is a positive number
3.descending would be a negative number
4. credit card charge would be a positive number
The answer is b :( hope it helps
