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andrezito [222]

3 years ago

11

An exam consists of 10 true-or-false questions. If a student guesses at every answer, what is the probability that he or she wil

l answer exactly 6 questions correctly?

1 answer:

Bond [772]3 years ago

5 0

1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 1/64.

I think there is is 1/64 chance.

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B.<br> cups of water fill<br> 14<br> Identical water bottles. How many cups fill each bottle?

11111nata11111 [884]

Answer:

bro how many cups fill 14 indentical water bottles

Step-by-step explanation:

question is in complete

or if I take it as x then x/14

hope it helps you

mark me as brainlist

7 0

3 years ago

Classify the triangle by its angles and sides.

liraira [26]

Answer:

obtuse scalene since 6 square plus 5 square is 36+25= 61, and 8 squared is 64, so 61<64, and if the legs are less than the hypotenuse, it would be an obtuse triangle. all the side are also unequal so it's a scalene.

4 0

3 years ago

Read 2 more answers

Solve for n. 8 3/4 + n + 2 3/8 + 4 1/2 = 23 1/8 A. 7 1/2 B. 8 3/8 C. 15 5/8 D. 8 4/8

Sonbull [250]

You can change all of these to decimals and then solve or get common denominators.
8.75 + n + 2.375 + 4.5 = 23.125
15.625 + n = 23.125
Subtract 15.625 from both sides
n = 7.5

8 0

3 years ago

In a triangle the ratio of angles is 2:3:4 find the angles

Dmitry [639]

Answer:

40,60,80

Step-by-step explanation:

2x+3x×4x=180

9x=180

x=20

2x=40

3x=60

4x=80

6 0

3 years ago

Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side

lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

=cot x (sec²x)²

=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]

= cot x(1+ 2 tan²x +tan⁴x)

=cot x+ 2 cot x tan²x+cot x tan⁴x

=cot x +2 tan x + tan³x [ ∵cot x tan x $=\frac{ \textrm{tan x }}{\textrm{tan x}}$ =1]

=R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

L.H.S =(sin x)(tan x cos x - cot x cos x)

= sin x tan x cos x - sin x cot x cos x

$=\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}$

= sin²x -cos²x

=1-cos²x-cos²x

=1-2 cos²x

=R.H.S

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

= $1+\frac{{sin^2x}}{cos^2x}$ [ $\textrm{sec x}=\frac{1}{\textrm{cos x}}$ ]

=1+tan²x $[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]$

=sec²x

=R.H.S

4.

$\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}$

L.H.S= $\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}$

$=\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}$

$=\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}$

$=\frac{\textrm{2sin x}}{sin^2 x}$

= 2 csc x

= R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

= sec²x-tan²x

= $\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}$

$=\frac{1- sin^2x}{cos^2x}$

$=\frac{cos^2x}{cos^2x}$

=1

8 0

4 years ago