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aksik [14]
3 years ago
5

Can anyone help me with this, I don't understand it at all. Thank you!

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

I would say your answer is option C.

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A triangle has an area of 12 square millimeters. What could be the measures of the base and height of the triangle in millimeter
Taya2010 [7]

A = bh/2

12= bh/2

bh = 24

We need to find pairs that multiply to 24

Answer:    b=3 and h=8 ,  b=6 and h=4, b=12 and h=2​

8 0
3 years ago
6/3 + (-1/6) = ?<br><br> (These are supposed to be fractions)
Phoenix [80]

Answer: 11/6 or 1 5/6

<u>Simplify 6/3</u>

6/3÷3/3=2/1

<u>Change 2/1</u>

2/1×6/6=12/6

New Problem: 12/6+(-1/6)

<u>Add</u>

12+-1/6=11/6

<u>Simplify</u>

11/6 = 1 5/6

6 0
3 years ago
What does the absolute value of the y coordinate tell you?
DENIUS [597]

Step-by-step explanation:

in x ,y =0

in y ,x =0

i think its thik ok dont mind if its wrong

7 0
3 years ago
Suppose you are making granola bars with 3 cups of oats. How much quinoa, flaxseed, and soy protein would you use would you need
Andreas93 [3]

Answer: \frac{3}{4}\ cup of quinoa, \frac{3}{8}\ cup of flaxseed, 1\ cup of soy protein.

Step-by-step explanation:

<h3> The missing table is attached.</h3>

Let be "q" the amount of cups of quinoa you'd need to use making the granolas with 3 cups of oats.

Based on the table you can write the following proportion:

\frac{\frac{1}{2} }{2}=\frac{q}{3}

Solving for "q", you get:

\frac{1}{4}=\frac{q}{3}\\\\q=\frac{3}{4}

 Let be "f" the amount of cups of flaxseed you'd need to use making the granolas with 3 cups of oats.

With the data given in the table you can write the following proportion:

\frac{\frac{1}{4} }{2}=\frac{f}{3}

Solving for "f", you get:

\frac{1}{8}=\frac{f}{3}\\\\f=\frac{3}{8}

Let be "s" the amount of cups of soy protein you'd need to use making the granolas with 3 cups of oats.

Using the table you can write this proportion:

\frac{\frac{2}{3} }{2}=\frac{s}{3}

Solving for "s", you get:

\frac{1}{3}=\frac{s}{3}\\\\s=1

6 0
3 years ago
What is the solution to the system of equations?<br><br> 6x – 9y = 16<br><br> 2x – 3y = 7
kifflom [539]
The first step for solving this problem is to multiply both sides of the bottom equation by -3.
\left \{ {{6x-9y=16} \atop {-6x + 9y = -21}} \right.
Add the two equations together.
6x - 9y - 6x + 9y = 16 - 21
Eliminate the opposites.
-9y + 9y = 16 - 21
Remember that the sum of two opposites equals 0,, so the equation becomes the following:
0 = 16 - 21
Calculate the difference on the right side of the equation.
0 = -5
This means that the statement \left \{ {{6x-9y=16} \atop {2x-3y=7}} \right. is false for any value of x and y. That means that the answer to your question is (x,y) ∈ ∅,, or no solution.
Let me know if you have any further questions.
:)
8 0
3 years ago
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