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Lelechka [254]
3 years ago
9

Line CD passes through points C(1, 3) and D(4, –3). If the equation of the line is written in slope-intercept form, y = mx + b,

what is the value of b?
–5
–2
1
5
Mathematics
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

5

Step-by-step explanation:

First we need to find the slope

m = (y2-y1)/ (x2-x1)

   = (-3-3)/(4-1)

  =-6/3

  = -2

Then we can use point slope form to make the equation

y-y1 = m(x-x1)

y-3 = -2(x-1)

Distribute

y-3 = -2x+2

Add 3 to each side

y-3+3 = -2x+2+3

y = -2x+5

Since this is in slope intercept form, y = mx +b, the y intercept is 5

Sliva [168]3 years ago
3 0

Answer: D. 5

Step-by-step explanation: First we need to find the slope

m = (y2-y1)/ (x2-x1)

  = (-3-3)/(4-1)

 =-6/3

 = -2

Then we can use point slope form to make the equation

y-y1 = m(x-x1)

y-3 = -2(x-1)

Distribute

y-3 = -2x+2

Add 3 to each side

y-3+3 = -2x+2+3

y = -2x+5

Since this is in slope intercept form, y = mx +b, the y intercept is 5

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26,405,020

Step-by-step explanation:

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What is the approximate value of 200,000 x 200
Nesterboy [21]

it would be 40000000 because there there are 7 zeroes and then you and then you multiply the two twos together and then put it in the front.

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Determine the equation of the line passing through the points <br> (4,-1) and (-2,-4)
jenyasd209 [6]

Answer:

y = 1/2x - 3

Step-by-step explanation:

the slope:

m=\frac{-4-(-1)}{-2-4} =\frac{-4+1}{-6} =\frac{-3}{-6} =\frac{3}{6} =\frac{1}{2}

the equation:

with the point (4, -1)

y-(-1)=\frac{1}{2} (x-4)

y+1=\frac{1}{2}x-2

y=\frac{1}{2} x-2-1

y=\frac{1}{2} x-3

I hope this help you

8 0
3 years ago
Does anyone have the answers for all?
Shkiper50 [21]

Answer and Step-by-step explanation:

1-6

a.

What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.

<em><u>The order that works is second machine, then first machine.</u></em>

<u>Second Machine:</u>

y = (6)^{2} -6 = 36 - 6 = 30

Plug into first machine now.

<u>First Machine:</u>

y = \sqrt{(30) - 5}  = \sqrt{25} = 5

We see that the result is 5.

b. <em><u>If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.</u></em>

<em><u>However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.</u></em>

1-7. The absolute value of a value is the positive version of that value.

a. |54| = <em><u>54</u></em>

b. -|-7\frac{3}{5}| = -7\frac{3}{5}

c. |3| - |-1| = 3 - 1 = <em><u>2</u></em>

d. |2.2 - 5.13| = |-2.93| = <em><u>2.93</u></em>

1-8.

a.

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u>

<u>|  ||  ||  ||  ||  |</u>

<u>(5 boxes on each side)</u>

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u> <u>   </u>

<u>|  ||  ||  ||  ||  ||  |</u>

<u>(6 boxes on each side)</u>

b.<em><u> The amount of squares on each side of the figure increases by 1.</u></em>

c. <em><u>There would be 1 square, because we know that the pattern is there is 2 squares added to the next figure, 1 at each end. If we go back a figure, we take away 2 squares.</u></em>

1-9.

a. -42 - 17 = <em><u>-59</u></em>

b. 8 - (-9) = 8 + 9 = <em><u>17</u></em>

c. 8(-9) = <em><u>-72</u></em>

d. -42 ÷ (-7) = <em><u>6</u></em>

e. -2(-3)(-4) = 6(-4) = <em><u>24</u></em>

f. -18 - 7 = <em><u>-25</u></em>

g. (-5)^{2} = <em><u>25</u></em>

h. -5^{2}  = -(5)^2 = -(25) = <em><u>-25</u></em>

i. \sqrt{49} = <em><u>7</u></em>

1-10.  x = 2 Plug 2 in for x, then solve.

a. y = 7 - 3(2) = 7 - 6 = <em><u>1</u></em>

b. y = (2)^2 -1 = 4 - 1 = <em><u>3</u></em>

c. y = \frac{18}{2} = <em><u>9</u></em>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u>I hope this helps!</u></em>

8 0
3 years ago
Get the general term for the sequence being your t3 = 11 and the t20 = 244.2
marusya05 [52]

Answer:

nth term = t_{n} = 7.639(1.2)^{n - 1}

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = t_{3} = ar^{2} = 11 .......... (1) and  

20th term = t_{20} = ar^{19} = 244.2 ........... (2)

Now, dividing equation (2) with equation (1) we get

\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2

⇒ r^{17} = 22.2

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = t_{n} = 7.639(1.2)^{n - 1} (Answer)

5 0
3 years ago
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