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uysha [10]
3 years ago
9

The uncertainty in the measurement 0.0035 mg is:_______ A) + 0.1 mg B) + 0.01 mg C) 0.001 mg D) + 0.0001 mg

Chemistry
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:

The correct option is (D).

Explanation:

Uncertainty means lack of certainty in any calculations. It is the quantification of doubts after the calculations are done.

In this problem, we need to find the uncertainty in the measurement 0.0035 mg. There are 4 numbers after decimal. It means uncertain digit 1/10000 is the smallest scale division.

Hence, the uncertainty in the measurement 0.0035 mg is +0.0001 mg

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Explanation:

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3 years ago
A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
3 years ago
Need these 2 answered asap pls
Kitty [74]

Answer:

im not a brain wiz but i think 20

Explanation:

3 0
3 years ago
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3 0
4 years ago
What are kind and number of atoms in ring portion in the haworth structure of glucose
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The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.

3 0
3 years ago
Read 2 more answers
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