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AlexFokin [52]
2 years ago
14

How many moles contain 5.34 x 10^26 atoms of iron?

Chemistry
1 answer:
SCORPION-xisa [38]2 years ago
6 0

Answer: 1.31 × 10^47 sorry if its not the answer

Explanation:

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Arrange the steps typically followed in the data preparation process in the order of occurrence. (Place the first step at the to
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Data validation → editing data → entry data → tabulation

This enables better integration, consumption and analysis of larger datasets using advanced business intelligence with analytics solutions.

<h3>What is data preparation ?</h3>

Data collection, combination, structure, and organisation are all steps in the process of preparing data for use in business intelligence (BI), analytics, and data visualisation applications.

  • Data prep is a common colloquial term for data preparation. It is also referred to as "data wrangling," while other professionals use that phrase more specifically to mean "cleaning, structuring, and transforming data." This usage distinguishes data wrangling from the data pretreatment stage.

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1 year ago
Which of the following processes does our Sun and other stars in our galaxy use to create energy?
Usimov [2.4K]

Answer:

fusion reaction

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Explanation:

hope this helps

5 0
3 years ago
When zinc nitrate is heated, zinc oxide, nitrogen dioxide(NO2) and oxygen gas are
laiz [17]

Answer:

i) 16.5g of ZnO

ii) 9.8 dm³ of NO2

Explanation:

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6 0
3 years ago
Which mineral(s) might you be examining if you place some hydrochloric (hcl) acid on a sample and it fizzes?
makvit [3.9K]
The minerals that one might be examining if you place some hydrochloric acid on a sample and it fizzes are Calcite and Dolomite.
Calcite and dolomite are very similar minerals. Both have the same hardness, the same rhombohedral cleavage, and are found in identical geologic settings. The best way to tell one from the other is the acid test; A drop of 1 M HCl on calcite produces an instant , obvious Fizz; a drop on dolomite produces slow or no obvious bubbling. 
4 0
3 years ago
If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol
igomit [66]

Answer:

\Delta _RH=4x10^{-3}\frac{kJ}{mol}

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}

Best regards.

5 0
3 years ago
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