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2 years ago

Brainliestttt UsaTestPrep

Mathematics

1 answer:

lianna [129]2 years ago

6 0

The answer to this question is:

36π cm³

your welcome.

Please brainliest

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18. Jameson and Quincy each deposit $7,000 into accounts that earn 6%

mina [271]

Answer:

Jameson will have about $267.58 less in his account than Quincy

Step-by-step explanation:

6 0

2 years ago

Anyone have these or know them???

horsena [70]

The answer would be y = 6x.

The reason for this is that when we add a number in front of x, it makes it go up vertically by the factor of that number. So if we are to stretch the graph vertically, the only way we can do it is by making 6 the coefficient.

8 0

2 years ago

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

2 years ago

One day at 3:00 a.m., the temperature was -13°F in Kodiak, Alaska. At 10:00 a.m., the temperature was 22°F. What was the average

suter [353]

-13 to 0 = 13 degrees changed. 0 to 22 is 22 degrees changed. 13 + 22 = 35 degree change.

10-3 = 7.

So there was a change of 35 degrees across 7 hours

35/7 = 5 degrees per hour.

6 0

2 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

Given that:

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the area of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

3 years ago