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3 years ago

What is the area of this figure?

Mathematics

2 answers:

finlep [7]3 years ago

8 0

Find the area of the 4 triangles.

12*10/2=60. There are two of the same dimensions, so the area so far is 120

12*18/2=108. There are also 2 of these, to the area of the bottom half is 216.
120+216=336.

lord [1]3 years ago

6 0

Two triangle areas of:

10*24/2+18*24/2

120+216

336 u^2

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aksik [14]

Answer:

The answer is D (6).

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3 years ago

In a fruit salad, there are 12 strawberries, 14 grapes, 6 kiwis, and 4 papayas. Find the ratio of kiwis to the total number of p

KonstantinChe [14]

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3 years ago

Read 2 more answers

A conical tent made of canvas has a base that is 34 feet across and a slant height of 12 feet to the nearest whole unit what is

RideAnS [48]

Check the picture below.

$\bf \textit{total surface area of a cone}\\\\
SA=\pi r\sqrt{r^2+h^2}+\pi r^2~~
\begin{cases}
r=radius\\
h=height\\
-------\\
r=17\\
\sqrt{r^2+h^2}=12
\end{cases}
\\\\\\
SA=\pi (17)(12)+\pi (17)^2\implies SA=204\pi +289\pi \implies SA=493\pi$

8 0

3 years ago

A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st

shutvik [7]

Answer:

Equation of movement y(t)

$y(t)=sin(10t-\pi/2)$

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

$A=1\,inch$

The period depends on the mass and the spring constant.

The formula for the period is:

$T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s$

The model y(t) for the movement of the mass-spring system is

$y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)$

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3 years ago

Evaluate m = for for m = 1 and (x1, y1) = (0, 2) and (x2, y2) = (x, 0).

77julia77 [94]

We know that
the slope formula is
m=(y2-y1)/(x2-x1)
(x1,y1)=(0,2)
(x2,y2)=(x,0)
m=1-----> equation 1
m=(0-2)/(x-0)------> m=-2/x -----> equation 2

equate equation 1 and equation 2
1=-2/x------> multiply by x both sides------> x=-2

the point (x2,y2) is ----------> (-2,0)

3 0

3 years ago