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zysi [14]
3 years ago
7

when solving the following system of equations by substitution what would be a correct first step x=y–7 3x+15y=-1

Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

The first step is to replace the value of x from the first equation with x in the second equation:

x=y-7

3x+15y=-1

3(y-7)+15y=-1        

3y-21+15y=-1

18y=-1+21

18y=20

y= \frac{20}{18} = \frac{10}{9}

x= \frac{10}{9} - 7

x=- \frac{53}{9}

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The windscreen wiper of a car sweeps
AVprozaik [17]

Answer:

A ≈ 530 cm²

Step-by-step explanation:

The swept area equals the total area covered by the blade minus the unswept area.

The area of a sector with radius r and angle θ is:

A = (θ / 360) πr²

So the swept area is:

A = (θ / 360) πR² − (θ / 360) πr²

A = (θ / 360) π (R² − r²)

A = (150 / 360) π (21² − 6²)

A ≈ 530 cm²

6 0
3 years ago
Given each polygon is regular find the measure of one of the interior angles
solmaris [256]
The answer would be 90 I think
4 0
3 years ago
Colby loves to download new music. He originally had 34 songs but plans to purchase 6 new songs each week. He wants to know how
g100num [7]
Week    # of Songs
1            34
2            34 + 6
3            34 + 6*2
4            34 + 6*3
...
n            34 + 6*(n - 1)

100        34 + 6* (100 - 1)

Answer: second option

5 0
3 years ago
Please help me!!! WITH MATH
Nataly [62]
1. I think A is 5 because it is the lower quartile range

2. The median of the data is 56 because the median of a plot is in the middle of the data

3. The greatest value of the data plot is 45 because it is higher than the rest of the numbers (upper quartile range).

4. The median of the plot is 41 because if you look at the box-whisker plot you can see that it is in the middle of the box

5. Your answer would be 42 because on a box-whisker plot, the first quartile is on the side of the box(first quartile).

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5 0
3 years ago
Read 2 more answers
Automobile mechanics conduct diagnostic tests on 150 randomly selected new cars of particular make and model to determine the ex
Archy [21]

Answer:

\mathbf{Margin\;  of\;  error} =  .0942816

Step-by-step explanation:

Given

Sample size n = 150

Sample proportion {\widehat{(p)} = \frac{42}{150} = 0.28

Confidence interval = \frac{99}{100} = .99

Margin\;  of\;  error = z_{\frac{\alpha }{2}}\sqrt{\frac{{\widehat{(p)}}{(1 - \widehat{p})}}{n}}

\alpha = 1 - confidence interval = 1 - 0.99 = .01

margin\;  of\;  error = z_{\frac{.01 }{2}}\sqrt{\frac{(.28) (1 - 0.28)}{150}    

For 99\% confidence interval

        ( Z = 2.576 )

margin\;  of\;  error = z_{.005 }}\sqrt{\frac{(.28) (1 - 0.28)}{150}                  

margin\;  of\;  error = 2.576\times\sqrt{\frac{(.28) (1 - 0.28)}{150}

                           =  .0942816

8 0
3 years ago
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