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jok3333 [9.3K]
3 years ago
11

A gas of 3.4 moles occupies a volume of 0.046 L at 298 K. What is the pressure in kPa?

Chemistry
1 answer:
Phantasy [73]3 years ago
3 0

Answer : The correct option is, 2.1\times 10^5kPa

Explanation :

To calculate the pressure of gas we are using ideal gas equation as:

PV=nRT

where,

P = pressure of gas = ?

V = volume of gas = 0.046 L

n = number of moles of gas = 3.4

R = gas constant = 8.314 L.kPa/mol.K

T = temperature of gas = 298 K

Now put all the given values in the above formula, we get:

P\times (0.046L)=(3.4mol)\times (8.314L.kPa/mol.K)\times (298K)

P=1.83\times 10^5kPa\approx 2.1\times 10^5kPa

Therefore, the pressure of gas is, 2.1\times 10^5kPa

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Q Q 3. (08.02 MC)
AnnyKZ [126]

Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Explanation:

Given: V_{1} = ?,         M_{1} = 0.55 M

V_{2} = 100.0 mL,        M_{2} = 2.50 M

Formula used to calculate the volume of KBr is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.55 M \times V_{1} = 2.50 M \times 100.0 mL\\V_{1} = 455 mL

Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

7 0
3 years ago
Read 2 more answers
How many molecules are contained in 103.4g of sulfuric acid?
Ierofanga [76]
<h3>Answer:</h3>

1.827 × 10²⁴ molecules H₂S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Compounds</u>

  • Writing Compounds
  • Acids/Bases

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

103.4 g H₂S (Sulfuric Acid)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 103.4 \ g \ H_2S(\frac{1 \ mol \ H_2S}{34.09 \ g \ H_2S})(\frac{6.022 \cdot 10^{23} \ molecules \ H_2S}{1 \ mol \ H_2S})
  2. Multiply:                                                                                                            \displaystyle 1.82656 \cdot 10^{24} \ molecules \ H_2S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

1.82656 × 10²⁴ molecules H₂S ≈ 1.827 × 10²⁴ molecules H₂S

4 0
3 years ago
The mole fraction of nitrogen in the air is 0.7808. this means that 78.08% of the molecules in the air are nitrogen. when the at
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Answer:

p = \boxed{\text{593 torr}}

Explanation:

For this question, we must use Dalton's Law of Partial Pressures:

The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:

p = \chi p_{\text{tot}}

Data:

χ = 0.7808

p_{\text{tot}} = \text{ 760 torr}

Calculation:

p = 0.7808 \times \text{ 760 torr}\\\\p= \boxed{\textbf{593 torr}}

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Based on molecular orbital theory, the bond orders of the H—H bonds in H 2 , H 2 + , and H 2 - are _________, respectively
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Answer:

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Explanation:

Bond order= Bonding electrons-antibonding electrons/2

In H2, there are two bonding electrons and no antibonding electrons. In H2+ there is only one bonding electron and no antibonding electron while in H22- there are two bonding and two antibonding electrons respectively.

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