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Alona [7]
3 years ago
8

Identify the name for the following compound: Al2O3

Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

Aluminium oxide (Al2O3)

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A mixture is made of 40 ml of salt water to 200 ml of solution. What percent of the solution is salt water?
Serggg [28]

Answer:

16.7%

Explanation:

40 ml of salt water + 200 ml of solution = 240 ml

40/240 = 4/24 = 1/6=16.7%

5 0
3 years ago
The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoa
iren [92.7K]
Molecular Formula of Propanoic Acid is....

                                                C₃H₆O₂
Where;

Atomic Mass of C  =  12

Atomic Mass of H  =  1

Atomic Mass of O  =  6

Substituting Atomic Masses in molecular formula,

                                                (12)₃ + (1)₆ + (16)₂

                                                   36  +  6  +  32

                                                        74 g/mol

Result:
            
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,

7 0
3 years ago
Earth rotates west to east. Is this true or false? I want to say false, but I'm not sure.
777dan777 [17]
The answer is false because it goes in a full 360 degree circle 
8 0
3 years ago
Read 2 more answers
Under what conditions is the change in internal energy, δe rxn , equal to the heat evolved in a chemical reaction?
Stells [14]
 the first law says that  the change in internal energy of a system is given by: 

δ<span>E = δq + δw</span>

where δ<span>E is the i change in internal energy, </span>

<span>δq is the amount of thermal energy added to the system from the surroundings </span>

<span>δw is the l work done *on* the system *by* the surroundings. </span>

<span>For a system only undergoing expansion work,
δw = -p</span>δ<span>V, so: </span>

δE = δq - p δ<span>V </span>
when δV = 0, then δe=δq
4 0
3 years ago
Explain why a solution that is 1.3 M HF and 1.3 mM KF is not a good buffer. HF is a strong acid and cannot be used in a buffer s
zavuch27 [327]

Answer:

The ratio of acid to conjugate base is outside the buffer range of 10:1.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}

A buffer should have

\dfrac{1}{10} \leq \dfrac{\text{[A$^{-}]$}}{\text{[HA]}} \leq \dfrac{10}{1}

For a solution that is 1.3 mol·L⁻¹ in HF and 1.3 mmol·L⁻¹ in KF, the ratio is

\dfrac{1.3 \times 10^{-3} }{1.3} = \dfrac{1}{1000}

The ratio of acid to conjugate base is 1000:1, which is outside the range of 10:1.

A is wrong. NF is a weak acid.

C is wrong. The two species are a conjugate acid-base pair.

D is wrong. Salts of Group 1 metals are soluble.

4 0
3 years ago
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