What are the three major life processes that have to occur in animal cells?

Chemistry

2 answers:

Gwar [14]3 years ago

7 0

1- Movement
2- Respiration
3- Growth

erastova [34]3 years ago

4 0

First you have Movement , Second there's Respiration and Third there's Growth.

i hope this helps you.

You might be interested in

Calculate the solubility (in grams per 1.00×102mL of solution) of magnesium hydroxide in a solution buffered at pH = 12

GaryK [48]

The Ksp of Mg(OH)2 in water is 1.8 x 10-11. This means that in pure water, Mg(OH)2 has a solubility of:
∛[(1.8 x 10-11) / 4] = 1.65 x 10-4 mol/L
which is equal to
1.65 x 10-4 mol x (58.32) / 10 x 100 mL = 9.62 x 10-4g / 1x102 mL

If the pH is 12, the hydroxide concentration in the solvent is
10^-(14-12) = 0.01 mol/L
The solubility is solve using the formula
1.8 x 10-11 = x (2(0.01 + x))^2
x = 4.5x10-8 mol/L
which is equal to
4.5x10-8 mol x (58.32) / 10 x 100 mL = 2.62 x 10-7g / 1x102 mL

8 0

4 years ago

Please explain this to me, it's taking forever for me!

liubo4ka [24]

Answer:

civic cgvvbbbibbbnn bnnnn

5 0

3 years ago

What is the sun internal structure of the sun?

ipn [44]

I hope this helps you...

From the center out, the layers of the Sun are as follows: the solar interior composed of the core (which occupies the innermost quarter or so of the Sun's radius), the radiative zone, and the the convective zone, then there is the visible surface known as thephotosphere, the chromosphere, and finally the outermost layer, the corona.

5 0

4 years ago

In a constant-pressure calorimetry experiment, a reaction gives off 22.8 kJ of heat. The calorimeter contains 150 g of water, in

ludmilkaskok [199]

Answer:

The final temperature of water is 56,7 ºC

Explanation:

We need to apply the specific heat capacity formula to solve this.

Q = m . C . ΔT

22,8 kJ = 150 g . 4,186 J/g °C . (Tfinal - 20,4º C)

(We need to convert kJ in J to use the specific heat of water, be careful with units)

22,8 kJ = 22800 J (x1000)

22800 J = 150 g . 4,186 J/g °C . (Tfinal - 20,4º C)

22800 J = 627,9 J/ºC (Tfinal - 20,4º C)

22800 J / 627,9 ºC/ J = (Tfinal - 20,4º C)

36,3ºC = Tfinal - 20,4º C

36,3ºC + 20,4º C = 56,7 ºC

7 0

4 years ago

An unknown element is determined to have 22 neutrons and a mass number of 40.

Amiraneli [1.4K]

It’s Calcium hope that helps!

7 0

3 years ago