Which of the following statements is FALSE?

BARSIC [14]

The easiest way to do this is to convert both of the numbers to improper fractions. so 10 becomes 10/1 and 3 1/6 becomes 19/6. Then we multiply straight across so 10*19 is 190 and 1*6 is 6 and we get 190/6. This can be simplified to 95/3 which is 31 2/3. Hope this helps.

6 0

3 years ago

Express the complex number in trigonometric form. -6 + 6 square root of 3 i ?

bagirrra123 [75]

$\bf \begin{array}{clclll}
-6&+&6\sqrt{3}\ i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\
-------------------------------\\\\$

$\bf r=\sqrt{(-6)^2+(6\sqrt{3})^2}\implies r=\sqrt{36+(6^2\cdot 3)}\implies r=\sqrt{144}
\\\\\\
r=12\leftarrow 
\\\\\\
\theta =tan^{-1}\left( \frac{6\sqrt{3}}{-6} \right)\implies \theta =tan^{-1}\left( -\sqrt{3}\right)\implies \theta =
\begin{cases}
\frac{2\pi }{3}\leftarrow \\
\frac{5\pi }{3}
\end{cases}$

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.

thus $\bf 12\left[cos\left( \frac{2\pi }{3} \right) +i\ sin\left( \frac{2\pi }{3} \right) \right]$

5 0

4 years ago

A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH

Burka [1]

Two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH : <u>rotation -90° and translation (0,2)</u>

<h3>Further explanation</h3>

There are several forms of transformation, including translation, dilation, rotation or reflection

There are 2 shapes of geometry:

Similar figures:

the same shape but different in size,

Congruent figures:

the same size and the same shape

Both polygons will appear congruent if, after being transformed, the two polygons will map exactly to each other

A sequence of two transformations e can do is :

1. rotation -90°

Let point H(4,1) from polygon GFJIH , we rotate -90°

$\left[\begin{array}{ccc}x'\\y'\end{array}\right]=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4-6\\1+1\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}-2\\2\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}8\\1\end{array}\right]$