The triangles are similar so corresponding sides will be in ratio. The first triangle has sides of 2, 4, and 6. The second triangle has a largest side of 24. You are asked to find the perimeter of the second triangle.
The largest side of the first triangle is 6 and the largest side of the second triangle is 24. This is a ratio of 6:24 which can be reduced to 1:4.
Each side of the second triangle is 4 times as large as the corresponding side of the first triangle.
Now we can calculate the other 2 sides.
2 x 4 = 8
4 x 4 = 16
The three sides are 8, 16 and 24
Perimeter of this triangle is 8 + 16 + 24 = 48
Answer:
69
Step-by-step explanation:
because 34plus 35 will give you 69
The ratio has a total of 2+3=5 units, of which 2 correspond to the length of segment AM. The difference of x-coordinates Bx-Ax = 20-0 = 20. 2/5 of that amount is (2/5)*20 = 8, so the x-coordinate of M is
Mx = 8 + Ax = 8 + 0 = 8
The difference of y-coordinates is 0 - 15 = -15. 2/5 of that amount is (2/5)*(-15) = -6, so the y-coordinate of M is
... My = -6 + Ay = -6 + 15 = 9
The point M is (Mx, My) = (8, 9).
Answer:
Step-by-step explanation:
hello :
look this solution
so leg A would be 60
leg B would be 85
using this we are able to determine the HYP to be 104.04
so sine = opp/HYP
leg A is the opp in this case
sin(theta) = 60/104.04
sin(theta) = 0.57670126874
when we round to the hundredths place we get 0.58
:dab: