Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
Answer:
5,022 Students
Step-by-step explanation:
All you have to do it multiply!
Like so:
81*62= 5,022
Given:
Area of a circle, A=50.265 sq. units.
Radius of circle, r = 4 units.
To find:
The value of π to the nearest thousandth.
Solution:
Formula for area of a circle is
Now, using 
expression, we can find the value of π.
Approximate the value to the nearest thousandth (three digits after decimal).
Therefore, the approximated value of π is 3.142.
