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2 years ago

Pls help I’ve been stuck for days

Mathematics

1 answer:

kolezko [41]2 years ago

6 0

Answer:

Step-by-step explanation:

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Problem 4 Solve x^2-8x=5

ra1l [238]

Answer:C

Step-by-step explanation:

x=4+√21,4−√21

Decimal Form:

8.58257569

0.58257569

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3 years ago

PLEASE I NEED HELP CLICK ON THIS IMAGE

Alecsey [184]

Answer:mean

Step-by-step explanation:

I would assume it’s the mean since that averages the 7 test scores it represents the data set well. Outlier and mode don’t describe a data set since they are quite unique within it.

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3 years ago

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3/8 + (-7/8) = ???? brianliest

ser-zykov [4K]

Answer:

-0.5

Step-by-step explanation:

just divide the numbers first then add them together

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3 years ago

John left a $2 tip for the server when stopped at a diner. If this was 20% of his order total, how much was his order?

Katen [24]

The answer is 10 dollars

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2 years ago

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someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago