Answer:
log[3(x+4)] is equal to log(3) + log(x + 4), which corresponds to choice number three.
Step-by-step explanation:
By the logarithm product rule, for two nonzero numbers 
and 
,
.
Keep in mind that a logarithm can be split into two only if the logarithm contains the product or quotient of two numbers.
For example, 
is the number in the logarithm ![\log{[3(x + 4)]}](https://tex.z-dn.net/?f=%5Clog%7B%5B3%28x%20%2B%204%29%5D%7D)
. Since is a product of the two numbers 
and 
, the logarithm can be split into two. By the logarithm product rule,
![\log{[3(x + 4)]} = \log{(3)} + \log{(x + 4)}](https://tex.z-dn.net/?f=%5Clog%7B%5B3%28x%20%2B%204%29%5D%7D%20%3D%20%5Clog%7B%283%29%7D%20%2B%20%5Clog%7B%28x%20%2B%204%29%7D)
.
However, 
cannot be split into two since the number inside of it is a sum rather than a product. Hence choice number three is the answer to this question.
Answer:
B all real numbers
Step-by-step explanation:
what is the domain of the function (B)
Answer: Choice C)
(x-2)(3x) + (x-2)(4)
======================================
How to get this answer? One easy way that might work is to let y = x-2, which will allow us to do a replacement.
We will go from (x-2)(3x+4) to y(3x+4). Now use the distributive property to multiply the y term by each term inside
y(3x+4) = y*3x + y*4 = (y)*(3x) + (y)*(4)
The last step is to re-introduce y = x-2 back in. So replace y with x-2 like so
(y)*(3x) + (y)*(4) = (x-2)*(3x) + (x-2)(4)
Answer:
3,3
Step-by-step explanation:
to simplify you just add the 3 from the right side to the left side 3y and 3x
