The zeros of given function 
is – 5 and – 3
<u>Solution:</u>
We have to find the zeros of the function by rewriting the function in intercept form.
By using intercept form, we can put value of y as to obtain zeros of function
We know that, intercept form of above equation is 
Taking “x” as common from first two terms and “3” as common from last two terms
x (x + 5) + 3(x + 5) = 0
(x + 5)(x + 3) = 0
Equating to 0 we get,
x + 5 = 0 or x + 3 = 0
x = - 5 or – 3
Hence, the zeroes of the given function are – 5 and – 3
Hey there!
Same question is answered by me correctly.
You can go and check the answer link given:
brainly.com/question/25169246
<u>Note:</u>
The answer in the given link is answered by me.
7 goes into 9, that's 1.
Remaining 2.
Move the 2 close to 3, you have 23.
7 into the 23, that's 3 times. 3 times 7 is 21.
So you are left with 2.
The answer is 13 remainder 2.
13\2\7
C, adding the rest of this sentence because it needs to be longer
Answer:
2
Step-by-step explanation:
(-7)^2 - 4*3 *(-2) = 49 + 24 >0
discriminant is positive so 2 real roots
