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fredd [130]
3 years ago
6

State the domain and range for the following relation. Then determine whether the relation represents a function.

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

C. Domain : {Gem, Hesh, Sam}

Range : {Gale, Abby, Beni}

B. The relation in the figure is a function because each element in the range corresponds to exactly one element in the domain.

Step-by-step explanation:

The figure of the mapping is attached below.

From the diagram, the domain for the relation is the set of Fathers:

{Gem, Hesh, Sam}

The range is the set of Sons:

{Gale, Abby, Beni}

The relation is a function. This is because each element in the range corresponds to exactly one element in the domain.

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  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.

Step-by-step explanation:

This problem involves two unknowns:

  • wind speed, and
  • speed of the plane in still air.

Let the speed of the wind be x \rm \; km \cdot h^{-1}, and the speed of the plane in still air be y\rm \; km \cdot h^{-1}. It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

  • It takes the plane three hours to travel \rm 960\; km from Ottawa to with a tail wind (that is: at a ground speed of x + y.)
  • It takes the plane four hours to travel \rm 960\; km from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of -x + y.)

Create a two-by-two system out of these two equations:

\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right..

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right..

\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right..

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only 1 \times 960 on the right-hand side. In comparison, adding them will give 7 \times 960, which is much more complex to evaluate. Subtracting the second equation (3 \times (2)) from the first (4 \times (1)) will give the equation

(12 - (-12) x = 1 \times 960.

24 x = 960.

x = 40.

Substitute x back into either equation (1) or (2) of the original system. Solve for y to obtain y = 320.

In other words,

  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.
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