5m : 100cm
= 5m : 1m
Therefore, the ratio is 5:1 which is answer c.
All of the above. Data is a thing that can be tracked no matter how much of it there is, so all apply.
Answer:
The 95% confidence interval based on this sample is =
[6.41, 7.79]
Step-by-step explanation:
The formula for Confidence Interval =
Mean ± z × standard deviation/√n
Sample mean = 7.1 hours
Standard deviation = 5 hours
n = 200 students
z = 95% confidence interval z score
= 1.96
C.I = 7.1 ± 1.96 × 5/√200
C.I = 7.1 ± 0.693
Hence, Confidence Interval
= 7.1 - 0.693
= 6.407
Approximately = 6.41
= 7.1 + 0.693
= 7.793
Approximately = 7.79
Therefore, the 95% confidence interval based on this sample is
[6.41, 7.79]
Answer:
$1545.65.
Step-by-step explanation:
We have been given that Victor has a credit card with an APR of 13.66%, compounded monthly. He currently owes a balance of $1,349.34.
To solve our given problem we will use compound interest formula.
, where,
A = Final amount after t years,
P = Principal amount,
r = Interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.
Let us convert our given interest rate in decimal form. ![13.66=\frac{13.66}{100}=0.1366](https://tex.z-dn.net/?f=13.66%3D%5Cfrac%7B13.66%7D%7B100%7D%3D0.1366)
Upon substituting our given values in compound interest formula we will get,
![A=1,349.34(1+\frac{0.1366}{12})^{12*1](https://tex.z-dn.net/?f=A%3D1%2C349.34%281%2B%5Cfrac%7B0.1366%7D%7B12%7D%29%5E%7B12%2A1)
![A=1,349.34(1+0.011383333)^{12](https://tex.z-dn.net/?f=A%3D1%2C349.34%281%2B0.011383333%29%5E%7B12)
![A=1.349.34(1.011383333)](https://tex.z-dn.net/?f=A%3D1.349.34%281.011383333%29)
![A=1,349.34*1.145485275522](https://tex.z-dn.net/?f=A%3D1%2C349.34%2A1.145485275522)
≈ $![1545.65](https://tex.z-dn.net/?f=1545.65)
Therefore, Victor will owe an amount of $1545.65 after one year.