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Oksana_A [137]
3 years ago
6

A 0.477 mol sample of O_2 gas has a volume of 11.3 L at a certain temperature and pressure. If all this O_2 were converted to oz

one (O_3) at the same temperature and pressure, what is the ozone volume (in liters)? 3 O_2(g) → 2 O_3(g)
Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

The volume of ozone produced is 7.53 L.

Explanation:

The reaction is:

3O₂(g)  →  2O₃(g)   (1)      

0.477 mol   V=?

11.3 L    

From the reaction (1) we have that 3 moles of O₂ produce 2 moles of O₃ so the volume of the ozone produced can be calculated as follows:

V_{O_{3}} = V_{O_{2}}*\frac{n_{O_{3}}}{n_{O_{2}}} = 11.3 L*\frac{2}{3} = 7.53 L

Therefore, the volume of ozone produced is 7.53 L.

I hope it helps you!

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