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Oksana_A [137]
3 years ago
6

A 0.477 mol sample of O_2 gas has a volume of 11.3 L at a certain temperature and pressure. If all this O_2 were converted to oz

one (O_3) at the same temperature and pressure, what is the ozone volume (in liters)? 3 O_2(g) → 2 O_3(g)
Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

The volume of ozone produced is 7.53 L.

Explanation:

The reaction is:

3O₂(g)  →  2O₃(g)   (1)      

0.477 mol   V=?

11.3 L    

From the reaction (1) we have that 3 moles of O₂ produce 2 moles of O₃ so the volume of the ozone produced can be calculated as follows:

V_{O_{3}} = V_{O_{2}}*\frac{n_{O_{3}}}{n_{O_{2}}} = 11.3 L*\frac{2}{3} = 7.53 L

Therefore, the volume of ozone produced is 7.53 L.

I hope it helps you!

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2 points
Westkost [7]

Answer:

Law of conservation of mass

Ernest Rutherford

Explanation:

The basic law of behavior of matter that states that "mass is neither created nor destroyed in a chemical reaction or physical change".

This is the law of conservation of mass. It is very essential in understanding most chemical reaction. Also, in quantitative analysis, this law is pivotal.

Ernest Rutherford was the scientist that stated that the nucleus is made up of positive charge. It was not until James Chadwick in 1932 discovered the neutron that we had an understanding of this nuclear component.

Rutherford surmised from his experiment that because most the alpha particles passed through the thin Gold foil and just a tiny fraction was deflected back, the atom is made is made up of small nucleus that is positively charged.

4 0
3 years ago
The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa
Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of MgCl_2 (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of MgCl_2 (solute) = 3.37 g

First we have to calculate the mass of solute.

\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2

\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g

Now we have to calculate the mass of solution.

\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0
3 years ago
HELPWITH THE QUESTIONS ALL OF THEM PLZZZZZ ASAPPPP
Klio2033 [76]

Answer:

Explanation:

ok i will get someone

4 0
2 years ago
What is the molar mass of fluorine
MissTica
THE MOLAR MASS OF FLUORINE IS 35G/MOL
5 0
3 years ago
Can somebody please help me please?
Phoenix [80]

Answer:

7.74%

<em>Hope this helped! Have a good day.</em>

8 0
2 years ago
Read 2 more answers
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