Answer:
Assuming pressure is held constant,the question reduces to a ratio and proportion type of question where;
At constant pressure,
21.0ft³-55.0°F
11.0fy³=11.0ft³/21.0ft³×55°F
The temperature is 28.809°F≈29°F
Answer:
H = m c ΔT
89.6 J = (20.0 g) × c × (40.0 - 30.0)°C
Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)
Yes, it would be the last one as the zeros that appear after a non zero number are significant.
Answer : The vapor pressure of water at 
is 1.01 atm.
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
or,
where,
= initial pressure = ?
= final pressure = 750 torr = 0.987 atm (1 atm = 760 torr)
= initial volume = 1.95 L
= final volume = 2.00 L
Now put all the given values in the above equation, we get:
Therefore, the vapor pressure of water at is 1.01 atm.
