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Sati [7]
2 years ago
6

Using the combined gas law above, identify the variables that would be in the numerator (A) and denominator (B) if you were to r

earrange the gas law to solve for final temperature.
T subscript 2 equals StartFraction A over B EndFraction.

Denominator (B):

P1V1T2

P2V2T1

T1V2

P1V1
Chemistry
1 answer:
ad-work [718]2 years ago
4 0

Answer:

The denominator B = P1V1

Explanation:

We'll begin by writing the combine gas equation. This is shown below:

P1V1/T1 = P2V2/T2

Where:

P1 is the initial pressure.

V1 is the initial volume.

T1 is the initial temperature.

P2 is the final pressure.

V2 is the final volume.

T2 is the final temperature.

Now let us make T2 the subject of the formula to obtain our desired result. This is illustrated below:

P1V1/T1 = P2V2/T2

Cross multiply to express in linear form

P1V1T2 = P2V2T1

Divide both side by P1V1

T2 = P2V2T1/P1V1

From the above illustration,

The numerator A = P2V2T1

The denominator B = P1V1

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In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water b
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2 years ago
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2 years ago
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7 0
2 years ago
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If the solubility of sugar at 25ºC is 211 g/100 g H2O, what mass of sugar can be dissolved in 300 g of H2O?
ladessa [460]

Answer:

633 grams of sugar can be dissolved in 300 g of H₂O

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