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Sati [7]
3 years ago
6

Using the combined gas law above, identify the variables that would be in the numerator (A) and denominator (B) if you were to r

earrange the gas law to solve for final temperature.
T subscript 2 equals StartFraction A over B EndFraction.

Denominator (B):

P1V1T2

P2V2T1

T1V2

P1V1
Chemistry
1 answer:
ad-work [718]3 years ago
4 0

Answer:

The denominator B = P1V1

Explanation:

We'll begin by writing the combine gas equation. This is shown below:

P1V1/T1 = P2V2/T2

Where:

P1 is the initial pressure.

V1 is the initial volume.

T1 is the initial temperature.

P2 is the final pressure.

V2 is the final volume.

T2 is the final temperature.

Now let us make T2 the subject of the formula to obtain our desired result. This is illustrated below:

P1V1/T1 = P2V2/T2

Cross multiply to express in linear form

P1V1T2 = P2V2T1

Divide both side by P1V1

T2 = P2V2T1/P1V1

From the above illustration,

The numerator A = P2V2T1

The denominator B = P1V1

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Explanation:

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3 years ago
If 3.5 g of element X reacts with 10.5 g of element Y to form the compound XY.
irina [24]

Answer:

The percentage by mass of element X is 25 %.

The percentage by mass of element Y is 75 %

Explanation:

X + Y ⇒ XY

3.5 g of element X + 10.5 g of element Y = 14g in total

⇒Element X : 3.5g / 14g = 0.25 ⇒ x 100 % = 25 %

⇒Element Y : 10.5 / 14 = 0.75 ⇒ x 100 % = 75 %

The percentage by mass of element X is 25 %.

The percentage by mass of element Y is 75 %

8 0
4 years ago
How would increasing the original concentration of a weak acid affect its ka and pka?
Inessa [10]

Answer: C. K_a would increase and pK_a would decrease.

Explanation:

HA\rightleftharpoons H^++A^-

initially conc.       c       0         0

At eqm.  c(1-\alpha)   c\alpha      c\alpha

The expression for dissociation constant is,

K_a=\frac{c\alpha\times c\alpha}{c(1-\alpha)}

for weak acid, \alpha is very very small , the expression will be,

K_a=\frac{c^2\alpha^2}{c}=c\alpha^2

K_a=c\alpha^2As k_a is directly proportional to concentration, the value of K_a would increase on increasing the concentration.

pK_a=log\frac{1}{K_a}

Thus if K_a would increase, pk_a would decrease.

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3 years ago
What should the IUPAC name for a binary covalent compound lack ?
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The answer to the question is "B. Roman Numerals"
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4 years ago
Read 2 more answers
Energy in the amount of 420 J is added to a 35 g sample of water at a temperature of 10°C. What is the final temperature of the
Vsevolod [243]

The <em>final temperature </em><em>of the</em><em> water, T2</em> = <em>38.57°C</em>

Temperature can be defined as a measure of the degree of hotness or coldness of a physical object (body). Thus, it is measured with a thermometer and its units are degree Celsius (°C), Fahrenheit (°F) and Kelvin (°K).

A calorie refers to the amount of heat required to raise the temperature of a gram of water by one (1) degree Celsius (1°C).

<u />

<u>Given the following data:</u>

  • Quantity of energy = 420J
  • Mass = 35 grams
  • Initial temperature, T1 = 10°C

The specific heat capacity of water is 4.2 J/g°C.

To find the final temperature of the water (T2):

Mathematically, the quantity of energy (heat capacity) is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • M represents the mass of an object.
  • C represents the specific heat capacity of water.
  • dt represents the change in temperature.

Substituting the values into the formula, we have;

420 = 3.5 \; * \; 4.2 \; * \;  dt

420 = 14.7 \; * \; dt\\\\dt = \frac{420}{14.7}

Change in temperature, dt = 28.57°C

Next, we would solve for the final temperature by using this formula;

dt = T2 - T1

28.57 = T_{2} - 10\\\\T_{2} = 28.57 \; + \; 10\\\\T_{2} = 38.57

<em>Final temperature, T2 = 38.57°C</em>

<em>Therefore</em><em>, </em><em>the</em><em> final temperature </em><em>of the</em><em> water, T2</em> is equal to <em>38.57°C</em>

For more information visit: brainly.com/question/22736508

7 0
3 years ago
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