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Sati [7]
3 years ago
6

Using the combined gas law above, identify the variables that would be in the numerator (A) and denominator (B) if you were to r

earrange the gas law to solve for final temperature.
T subscript 2 equals StartFraction A over B EndFraction.

Denominator (B):

P1V1T2

P2V2T1

T1V2

P1V1
Chemistry
1 answer:
ad-work [718]3 years ago
4 0

Answer:

The denominator B = P1V1

Explanation:

We'll begin by writing the combine gas equation. This is shown below:

P1V1/T1 = P2V2/T2

Where:

P1 is the initial pressure.

V1 is the initial volume.

T1 is the initial temperature.

P2 is the final pressure.

V2 is the final volume.

T2 is the final temperature.

Now let us make T2 the subject of the formula to obtain our desired result. This is illustrated below:

P1V1/T1 = P2V2/T2

Cross multiply to express in linear form

P1V1T2 = P2V2T1

Divide both side by P1V1

T2 = P2V2T1/P1V1

From the above illustration,

The numerator A = P2V2T1

The denominator B = P1V1

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Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta
shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0
3 years ago
What is pressure in relation to a gas?
labwork [276]

The pressure of a gas is the force that a gas exerts per unit area of the container.

Pressure is defined as force per unit area. Gas molecules are constantly colliding against the walls of the container. The pressure of the gas is the force the gas is exerting on its container.

Since temperature is defined as the average kinetic energy of the molecules of a gas then the higher the temperature, the faster the particles move.

The volume of a container refers the size if the container.

The pressure of a gas is inversely proportional to its volume according to Boyle's law. Thus implies that if the pressure of the gas goes up, the volume has to go down.

For a compound to be called an acid, it must contain H+ and H3O+ when dissolved in water.

For a compound to be called a base, the compound must dissolve in water to yield hydroxide ions.

Learn more: brainly.com/question/11543614

7 0
2 years ago
Part 1. determine the molar mass of a 0.458-gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm. show your work.
d1i1m1o1n [39]
  • The molar mass of 0.458-gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm is 9.15g/mol.
  • If this sample was placed under extreme pressure, the volume of the sample will decrease.

<h3>How to calculate molar mass?</h3>

The molar mass of a substance can be calculated by first calculating the number of moles using ideal gas law equation:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • T = temperature
  • R = gas law constant
  • n = no of moles

0.98 × 1.2 = n × 0.0821 × 287

1.18 = 23.56n

n = 1.18/23.56

n = 0.05moles

mole = mass/molar mass

0.05 = 0.458/mm

molar mass = 0.458/0.05

molar mass = 9.15g/mol

  • Therefore, the molar mass of 0.458-gram sample of gas having a volume of 1.20 l at 287 k and 0.980 atm is 9.15g/mol
  • If this sample was placed under extreme pressure, the volume of the sample will decrease.

Learn more about gas law at: brainly.com/question/12667831

8 0
2 years ago
What relationship exists between an enzyme and a catalyst?
shepuryov [24]

A catalyst is a chemical that increases the rate of a chemical reaction without itself being changed by the reaction. The fact that they aren't changed by participating in a reaction distinguishes catalysts from substrates, which are the reactants on which catalysts work. Enzymes catalyze biochemical reactions.

5 0
3 years ago
Read 2 more answers
Calculate the % Oxygen in NaHCO3
Alexxx [7]

Answer:

Molar mass of NaHCO3 = 84.00661 g/mo

Explanation:

This compound is also known as Baking Soda or Sodium Bicarbonate.

Convert grams NaHCO3 to moles  or  moles NaHCO3 to grams

Molecular weight calculation:

22.98977 + 1.00794 + 12.0107 + 15.9994*3

3 0
3 years ago
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