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loris [4]
3 years ago
14

If 6.5 L of water is added to 4.5 L of a 2.8 M Ca(OH)2 solution, what is the molarity of the new solution?

Chemistry
1 answer:
Mila [183]3 years ago
6 0
Find moles of Ca(OH)2 first:

moles = 2.8 x 4.5 = 12.6

Now,
   After addition, new volume =  6.5 + 4.5 = 11.0

So, new molarity =  12.6 / 11 = 1.145
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if you were to compare the mass of the products and reactants in a reaction, you would find that the mass of the products is alw
Salsk061 [2.6K]
If you were to compare the mass of the products and reactants in a reaction, you would find that the mass of the products is <span>equal to the mass of the reactants.</span>
3 0
3 years ago
Answer choices:<br> A. Glass<br> B. Plastic <br> C. aluminum <br> D. Foam
Alona [7]

Answer:

I'm taking a guess here. Aluminum.

Explanation:

The best conductor of heat would be the material that melted the ice fast. A.K.A. the one with the least amount of minutes. Since aluminum has the least, it is the best conductor of heat

4 0
3 years ago
Read 2 more answers
It is 762 miles from here to Chicago. An obese physics teacher jogs at a rate of 5.0 miles every 20.0 minutes. How long would it
Lina20 [59]

Answer:

3,048 minutes

Explanation:

762 divided by 5

that number times 20

5 0
3 years ago
Assume that Aluminum and Silver Sulfide are the starting substances (reactants) in the reaction: a. Write a balanced chemical eq
Naddik [55]

Answer:

Check Explanation

Explanation:

a) The balanced chemical reaction between Aluminium and Silver Sulfide is represented below

2Al + 3Ag₂S → Al₂S₃ + 6Ag

Aluminium displaces Silver from Silver sulfide because it is higher than Silver in the electrochemical series.

b) Names of the products from this reaction

Ag is called Silver metal. Free Silver metal.

Al₂S₃ is called Aluminium Sulfide.

c) This reaction is a single-displacement reaction because an element directly displaces and replaces another element in a compound.

It is also a redox reaction (reduction-oxidation reaction) because there are species being oxidized and reduced simultaneously!

d) Yes, this reaction is an oxidation-reduction (redox) reaction because there are species being oxidized and reduced simultaneously!

e) The specie that is being oxidized is said to undergo oxidation. And oxidation is defined as the loss of electrons, thereby leading to an increase in oxidation number.

In this reaction, it is evident that Aluminium undergoes oxidation as its oxidation number increases from 0 in the free state to +3 when it displaces Silver and becomes Aluminium sulfide.

Al → Al³⁺

0 → +3 (Oxidation)

The specie that is being reduced is said to undergo reduction. And reduction is defined as the gain of electrons, thereby leading to a decrease in oxidation number.

In this reaction, it is evident that the silver ion undergoes reduction as its oxidation number decreases from +1 in the Silver Sulfide compound to 0 when it is displaced and becomes Silver in free state.

Ag⁺ → Ag

+1 → 0 (Reduction)

The reducing agent is the specie that brings about reduction. Since Silver ion in Silver sulfide is reduced, Aluminium is the reducing agent that initiates the reduction process.

The oxidation agent is the specie that brings about oxidation. Since, Aluminium is the specie that undergoes oxidation, the oxidizing agent is the Silver Sulfide that brings about the oxidation.

Hope this Helps!!!

6 0
3 years ago
A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
umka2103 [35]

Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

          mass of solute = 11.1 x 482 / 100

3.- Simplification

          mass of solute = 5350.2 / 100

4.- Result

          mass of solute = 53.5g

6 0
3 years ago
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