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loris [4]
3 years ago
14

If 6.5 L of water is added to 4.5 L of a 2.8 M Ca(OH)2 solution, what is the molarity of the new solution?

Chemistry
1 answer:
Mila [183]3 years ago
6 0
Find moles of Ca(OH)2 first:

moles = 2.8 x 4.5 = 12.6

Now,
   After addition, new volume =  6.5 + 4.5 = 11.0

So, new molarity =  12.6 / 11 = 1.145
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Which statement is right please explain giving brainliest
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Answer:

D

Explanation:

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Below is a diagram showing the chemical energy (Ech) for the formation of water. Is the reaction exothermic or endothermic?
BigorU [14]

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For a solution of acetic acid (CH3COOH) to be called “vinegar,” it must contain 5.00% acetic acid by mass. If a vinegar is made
emmasim [6.3K]

Answer:

  • M = 0.838 M

Explanation:

<u>1) Data:</u>

<u />

a) Acetic acid CH₃COOH

b) molar mass of CH₃COOH: 60.052 g/mol

c) %: = 5.00%

d) d = 1.006 g/ml

e) M = ?

<u>2) Formulae:</u>

a) M = n of solute / V of solution in liters

b) n = mass in grams / molar mass

c) % = (mass of solute / mass of solution)×100

d) d = mass  / volume

<u>3) Solution:</u>

a)<u> Assume a basis </u>

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b) <u>Calculate the mass of that basis (1 liter of solution)</u>

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c) <u>Calculate the mass of solute</u>

<u />

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<u />

  • n = mass in grams / molar mass = 50.3 g / 60.052 g/mol =  0.838 mol

e) <u>Calculate molarity</u>

  • M = n / V in liter = 0.838 mol / 1 liter = 0.838 M ← answer
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3 years ago
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Licemer1 [7]

Answer:

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Answer and explanation:

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