Question

A television screen measures approximately 15.5 inches high and 19.5 inches wife. A television is advertised by giving the approximate length of the diagonal of its screen. How should this television be advertised?

Answer 1

Answer:

Television should be advertised by 24.9≈25 inches.

Step-by-step explanation:

Height of television = 15.5 inches

Width of television =  19.5 inches

Since we are given that A television is advertised by giving the approximate length of the diagonal of its screen.

So, to calculate  How should this television be advertised refer the attached figure

Television is in shape of rectangle

AB = CD = 15.5 inches

AD = BC = 19.5 inches

So, To find the length of diagonal DB , we will use Pythagoras theorem in ΔABD

$Hypotenuse^{2} =Perpendicular^{2} + Base^{2}$

$DB^{2} =AB^{2} + AD^{2}$

$DB^{2} =15.5^{2} + 19.5^{2}$

$DB^{2} =620.5$

$DB = \sqrt{620.5}$

$DB =24.9$

Hence Television should be advertised by 24.9≈25 inches.