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Sindrei [870]
3 years ago
12

Evaluate the equation when x = 2, y = -1, and z =3 y/z+3y

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0
-1/3+6
17/3

(Mark me the brainliest if this was helpful)
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\huge \mathbb{\green{\fbox{\pink{ANSWER}}}}

\\  \:  \:  \implies \: sin^{4} \: \theta + cos^{4} \: \theta \rightarrow  \blue{ \frac{1}{2} }

\\ \\ \:  \large \mathfrak \green{Solution}  :

\\  \bf  \: Given :

\\ \sf \: \:  \bf sin \: \theta - cos \: \theta = 0

\\ \sf \rightarrow \: sin \:  \theta = cos \: \theta

\\ \sf \rightarrow \: \frac{sin \: \theta} {cos \: \theta} = 1

\\ \sf \rightarrow \: tan \: \theta = 1

\\ \sf \rightarrow \: tan \: \theta = tan \: 45 \degree

\\ \sf \rightarrow \: \theta = 45 \degree

\\ \\ \therefore \:  sin^{4} \: \theta + cos^{4} \: \theta

\\ \sf \rightarrow \: sin^{4} \: 45 \degree + cos^{4} \: 45 \degree

\\ \\\sf \rightarrow \: (\frac{1}{ \sqrt{2} } ) ^{4}  +(\frac{1}{ \sqrt{2} } ) ^{4}

\\ \sf \rightarrow \: ( \frac{1}{  \cancel {\sqrt{2} }}  )^{ \cancel{2}} ( \frac{1}{  \cancel{ \sqrt{2} }}  )^{\cancel{2}} + ( \frac{1}{  \cancel {\sqrt{2} }}  )^{ \cancel{2}} ( \frac{1}{  \cancel{ \sqrt{2} }}  )^{\cancel{2}}

\\ \\\sf \rightarrow \: \frac{1}{2} × \frac{1}{2} + \frac{1}{2}× \frac{1}{2}

\\ \\ \sf \rightarrow \: \frac{1}{4} +  \frac{1}{4}

\\ \\ \sf \rightarrow \: {\cancel \frac{2} {4}}

\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf  \implies \fbox{\pink {\frac{1}{2}}}

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Step-by-step explanation:

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